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MaRussiya [10]
3 years ago
12

What is the value of p such that the line passing through (6,2) and (9,p) has a slope of -1?

Mathematics
1 answer:
Aleks [24]3 years ago
4 0

Answer:

p= -1

Step-by-step explanation:

gradient=<u>y</u><u>²</u><u>-</u><u>y</u><u>¹</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>x²-x¹

-1 =<u>p</u><u>-</u><u>2</u>

<u> </u><u> </u><u> </u><u> </u><u> </u>9-6

-1=<u>p</u><u>-</u><u>2</u>

<u> </u><u> </u><u> </u><u> </u><u> </u> 3

multiply both sides by 3 to remove the denominators

-1×3=p-2

-3=p-2

put the like terms together

-3+2=p

-1=p

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