Answer:
$8750.87
Explanation:
This is compound interest problem. The formula used to solve this would be:
![F=P(1+r)^t](https://tex.z-dn.net/?f=F%3DP%281%2Br%29%5Et)
Where
F is the future value (what we want, after 3 years)
P is the initial value (given 6900)
r is the rate of interest per period
here, 8% per year, so 8/4 = 2% per period (since compounded per quarter)
t is the time (3 years and compounding per year so times of compounding is 3*4 = 12), so t = 12
Substituting, we get our answer:
![F=P(1+r)^t\\F=6900(1+0.02)^{12}\\F=6900(1.02)^{12}\\F=8750.87](https://tex.z-dn.net/?f=F%3DP%281%2Br%29%5Et%5C%5CF%3D6900%281%2B0.02%29%5E%7B12%7D%5C%5CF%3D6900%281.02%29%5E%7B12%7D%5C%5CF%3D8750.87)
<u>There will be about $8750.87 at the account at the end of 3 years!</u>