Given:
K = 0.71 = Kp
The reaction of sulphur with oxygen is
S(s) + O2(g) ---> SO2(g)
initial Pressure 6.90 0
Change -x +x
Equilibrium 6.90-x x
Kp = pSO2 / pO2 = 0.71 = x / (6.90-x)
4.899 - 0.71x = x
4.899 = 1.71x
x = 2.86 atm = pressure of SO2 formed
temperature = 950 C = 950 + 273.15 K = 1223.15 K
Volume = 50 L
Let us calculate moles of SO2 formed using ideal gas equation as
PV = nRT
R = gas constant = 0.0821 L atm / mol K
putting other values
n = PV / RT = 2.86 X 50 / 1223.15 X 0.0821 = 1.42 moles
Moles of Sulphur required = 1.42 moles
Mass of sulphur required or consumed = moles X atomic mass of sulphur
mass of S = 1.42 X 32 = 45.57 grams or 0.04557 Kg of sulphur
Answer:
<h2>2 m</h2>
Explanation:
The wavelength of a wave can be found by using the formula

where
c is the speed of the wave
f is the frequency
From the question
c = 5 m/s
f = 2.5 Hz
We have

We have the final answer as
<h3>2 m </h3>
Hope this helps you
Answer:
natural selection
Explanation:
it is a biological selection of genes, whether dominant or negative.
Answer:
C. Oxidation occurs at the anode and reduction occurs at the cathode.
Choice number third is the correct option for the given question
Explanation:
Copper and silver nitrate are the two components that form a voltaic cell. These are the two main ingredients which make the Redox reaction possible. The dog reaction that is taking place result in development of charge.
Since copper here is the anode in the reaction oxidation happens here by the solution
is cathode this is where reduction takes place.