2Li + 2H2O —> 2LiOH + H2
If I am having trouble, I usually take the most complicated compound, which in this case would be LiOH, and I add a 2 to the front of it. Then I go from there, and the problem is usually much easier to solve :)
Answer:
N₂O₅
Explanation:
From the question given above, the following data were obtained:
Mass of compound = 7.546 g
Mass of nitrogen (N) = 1.957 g
Empirical formula =?
Next, we shall determine the mass of oxygen present in the compound. This can be obtained as follow:
Mass of compound = 7.546 g
Mass of nitrogen (N) = 1.957 g
Mass of Oxygen (O) =?
Mass of O = (Mass of compound) – (Mass of N)
Mass of O = 7.546 – 1.957
Mass of O = 5.589 g
Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:
Mass of nitrogen (N) = 1.957 g
Mass of oxygen (O) = 5.589 g
Divide by their molar mass
N = 1.957 / 14 = 0.14
O = 5.589 / 16 = 0.35
Divide by the smallest
N = 0.140 / 0.14 = 1
O = 0.35 / 0.14 = 2.5
Multiply through by 2 to express in whole number
N = 1 × 2 = 2
O = 2.5 × 2 = 5
The empirical formula of the compound is N₂O₅.
Answer:
5.48 g
Explanation:
The concentration in M represents the mol/L, or the number of moles in each L of the solution, and it can be calculated by the number of moles (n) divided by the volume of the solution (V) in L, so:
M = n/V
1.71 = n/0.100
n = 0.171 mol
The molar mass of methanol is 32.04 g/mol, and it is the mass (m) divided by the number of moles:
FM = m/n
32.04 = m/0.171
m = 5.48 g
<span><span>this is the balance equation: 2SO2 </span>+ <span>O2 </span>→ <span>2SO3</span></span><span>.
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The definition of authentic is something that is original or true and not a copy of anything else.
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Hope it helps...</h2>