Sodium bromide equation
1 answer:
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Answer: Thus is a secondary alkanol.
Explanation:
Alkanol are compounds which contains carbons bonded by single bonds and contains hydroxy (-OH) as functional group.
Primary alkanol are those compounds which contain hydroxyl group attached a carbon which is further attached to a single carbon atom. Example: and
Secondary alkanol are those compounds which contain hydroxyl group attached to a carbon which is further attached to two more carbon atoms.Example:
Tertiary alkanol are those compounds which contain hydroxyl group attached to a carbon which is further attached to three more carbon atoms. Example:
Thus is a secondary alkanol.
Answer:
17.18 moles of NaCl are in 2,719 mL of a 6.32 M solution.
Explanation:
We have:
Molarity of the NaCl solution = 6.32 M
Volume of the NaCl solution = 2,719 mL =2,719 × 0.001 L= 2.719 L
1 mL = 0.001 L
Let the moles of NaCl be n.
17.18 moles of NaCl are in 2,719 mL of a 6.32 M solution.