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quester [9]
3 years ago
9

Which statement about oxidation and reduction in a voltaic cell is true? A. Both oxidation and reduction occur at the anode. B.

Both oxidation and reduction occur at the cathode. C. Oxidation occurs at the anode and reduction occurs at the cathode. D. Oxidation occurs at the cathode and reduction occurs at the anode.
Chemistry
1 answer:
Anettt [7]3 years ago
6 0

Answer:

C. Oxidation occurs at the anode and reduction occurs at the cathode.

Choice number third is the correct option for the given question

Explanation:

Copper and silver nitrate are the two components that form a voltaic cell. These are the two main ingredients which make the Redox reaction possible. The dog reaction that is taking place result in development of charge.

Since copper here is the anode in the reaction oxidation happens here by the solutionAgNO_3 is cathode this is where reduction takes place.

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dezoksy [38]

Answer:

20000 Mg

Explanation:

5 0
3 years ago
Atoms of the same chemical element that have different atomic mass are known as?
monitta

Answer:

isotopes

Explanation:

The atoms of a chemical element can exist in different types. These are called isotopes. They have the same number of protons (and electrons), but different numbers of neutrons. Different isotopes of the same element have different masses.

8 0
3 years ago
consider a different titrant for this exercise. suppose ca(oh)2 were used as the titrant, instead of naoh. this will make the ti
Ivan

The titrant for this exercise. suppose Ca(OH)₂ were used as the titrant, instead of NaOH. This will make the titrant twice as concentrated in hydroxide ion. the analyte will still be HC₂H₃O₂. the stoichiometry ratio of  HC₂H₃O₂ to Ca(OH)₂ is 1 : 2.

The balanced reaction of the given condition as follow :

 Ca(OH)₂   +      2HC₂H₃O₂      ------>     Ca(C₂H₃O₂)₂     +    2H₂O

from the equation it is clear that stoichiometry of Ca(OH)₂ is 1 and the stoichiometry of HC₂H₃O₂    is 2. therefore the stoichiometry ratio of  HC₂H₃O₂ to Ca(OH)₂ is 1 : 2.

Thus, The titrant for this exercise. suppose Ca(OH)₂ were used as the titrant, instead of NaOH. This will make the titrant twice as concentrated in hydroxide ion. the analyte will still be HC₂H₃O₂. the stoichiometry ratio of  HC₂H₃O₂ to Ca(OH)₂ is 1 : 2.

To learn more about stoichiometry here

brainly.com/question/13145466

#SPJ4

4 0
2 years ago
What is the molarity of a solution that is 26.0% by mass in phosphoric acid, H3PO4, and that has a density of 1.155 g/mL?
steposvetlana [31]

Answer: The molarity of a solution that is 26.0% by mass in phosphoric acid is 3.06 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

n = moles of solute

V_s =volume of solution in ml

Given : 26.0 g of phosphoric acid in 100 g of solution.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{26.0g}{98g/mol}=0.265moles

Volume of solution =\frac{\text {Mass of solution}}{\text {Density of solution}}=\frac{100g}{1.155g/ml}=86.6ml

Molarity=\frac{0.265\times 1000}{86.6ml}=3.06M

Molarity of a solution that is 26.0% by mass in phosphoric acid is 3.06 M

8 0
3 years ago
What is the initial temperature (°C) of a system that has the pressure decreased by 10 times while the volume increased by 5 tim
Ede4ka [16]

Answer:

300K

Explanation:

Given pressure of the system decreased by 10 times which means P_{2} =\frac{P_{1} }{10}

Given the volume of the system increased by 5 times which means V_{2} =5\times V_{1}

Given final temperature T_{2}=150K

Let the initial temperature be T_{1}

We know that PV=nRT

As n and R are constant \frac{PV}{T}=constant

\frac{P_{1}V_{1} }{T_{1}} =\frac{P_{2}V_{2}}{T_{2}}

T_{1} =\frac{P_1V_1}{P_2V_2} T_{2}

T_{1} =2\times T_{2}

T1=300K

8 0
3 years ago
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