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3 years ago

Find the limit of the function by using direct substitution as X approaches one lim(x^2-8x -2)

Mathematics

1 answer:

Leno4ka [110]3 years ago

8 0

Answer:

$lim_{x \to 1} x^2 -8x -2 =-9$

Step-by-step explanation:

For this case we want to find the following limit:

$lim_{x \to 1} x^2 -8x -2$

And we can find the limit distirbuting into each term like this:

$\lim_{x \to 1} x^2 -8 lim_{x \to 1} x -lim_{x \to 1} 2$

And replacing we got:

$1^2 - 8*1 -2 = 1-8-2 = -9$

So then the final answer for this case is:

$lim_{x \to 1} x^2 -8x -2 =-9$

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What is the answer for -8n=13

KatRina [158]

Answer:

-13/8

Step-by-step explanation:

u divied by -8 to get n by itself

4 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%2Bx-3%29%3A%20%28x%5E%7B2%7D%20-4%29%5Cgeq%201" id="TexFormula1" title="(x^{

Jlenok [28]

Answer:

$x>2$

Step-by-step explanation:

When given the following inequality;

$(x^2+x-3):(x^2-4)\geq1$

Rewrite in a fractional form so that it is easier to work with. Remember, a ratio is another way of expressing a fraction where the first term is the numerator (value over the fraction) and the second is the denominator(value under the fraction);

$\frac{x^2+x-3}{x^2-4}\geq1$

Now bring all of the terms to one side so that the other side is just a zero, use the idea of inverse operations to achieve this:

$\frac{x^2+x-3}{x^2-4}-1\geq0$

Convert the (1) to have the like denominator as the other term on the left side. Keep in mind, any term over itself is equal to (1);

$\frac{x^2+x-3}{x^2-4}-\frac{x^2-4}{x^2-4}\geq0$

Perform the operation on the other side distribute the negative sign and combine like terms;

$\frac{(x^2+x-3)-(x^2-4)}{x^2-4}\geq0\\\\\frac{x^2+x-3-x^2+4}{x^2-4}\geq0\\\\\frac{x+1}{x^2-4}\geq0$

Factor the equation so that one can find the intervales where the inequality is true;

$\frac{x+1}{(x-2)(x+2)}\geq0$

Solve to find the intervales when the equation is true. These intervales are the spaces between the zeros. The zeros of the inequality can be found using the zero product property (which states that any number times zero equals zero), these zeros are as follows;

$-1, 2, -2$

Therefore the intervales are the following, remember, the denominator cannot be zero, therefore some zeros are not included in the domain

$x\leq-2\\-2$

Substitute a value in these intervales to find out if the inequality is positive or negative, if it is positive then the interval is a solution, if it is negative then it is not a solution. This is because the inequality is greater than or equal to zero;

$x\leq-2$ -> negative

$-2$ -> neagtive

$-1\leq x$ -> neagtive

$x>2$ -> positive

Therefore, the solution to the inequality is the following;

$x>2$

6 0

2 years ago

Simplify <br><img src="https://tex.z-dn.net/?f=5%20%7B%20%7D%5E%7B2%7D%20%20-%204%20%7B%7D%5E%7B2%7D%20%20%3D%20" id="TexFormula

garri49 [273]

5 · 5 - 4 · 4 = 9 sorry if I'm wrong
the dots mean to multiply

5 0

2 years ago

Please help!!!!!!! Please help!!!!!! Please help!!!!!!

Nitella [24]

Answers:

Discrete
Continuous
Discrete
Continuous

==============================================

Explanations:

This is discrete because we can't have half a basketball, or any non-whole decimal value to represent the number of basketballs. We can only consider positive whole numbers {1,2,3,4,...}. A discrete set like this has gaps between items. In other words, the midpoint of 2 and 3 (the value 2.5) isn't a valid number of basketballs.
This is continuous because time values are continuous. We can take any two different markers in time, and find a midpoint between them. For example, the midpoint of 5 minutes and 17 minutes is 11 minutes since (5+17)/2 = 22/2 = 11. Continuous sets like this do not have any gaps between items. We can consider this to be densely packed.
This is the same as problem 1, so we have another discrete function. You either score a bullseye or you don't. We can't score half a bullseye. The only possible values are {1,2,3,4,...}
This is similar to problem 2. This function is continuous. Pick any two different positive real numbers to represent the amount of gallons of water. You will always be able to find a midpoint between those values (eg: we can have half a gallon) and such a measurement makes sense.

So in short, always try to ask the question: Can I pick two different values, compute the midpoint, and have that midpoint make sense? If so, then you're dealing with a continuous variable. Otherwise, the data is discrete.

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2 years ago

Can someone plz do the dimensional analysis for 32ft/6.45 sec to meters/min? Thank You!

Rzqust [24]

Answer:

About 90.73 meters/min.

Step-by-step explanation:

Dimensional analysis is done by multiplying the wanted unit over the current unit in equal measure, or the other way around.

First, we will convert feet to meters, using that 1 ft = .4048 m.

32ft/6.45sec * .3048m/1ft = 32/6.45sec * .3048m = 9.7536m/6.45 sec.

Second, we convert seconds to minutes, using that 60 sec = 1 min.

9.7536m/6.45sec * 60sec/1min = 9.7536*60m/6.45min ≈ 90.7311627m/min.

5 0

3 years ago