I am going to explain this using the substitution method, considering it appears to be the best in this situation.
We know (from the bottom equation) that y can equal 3x+20. Using this knowledge, we substitute the y in the top equation for 3x+20. Now, we have an equation that looks like this:
3x+20=x^2+2x
Now we need to move x to one side and then do some radicals (square roots).
Subtract the 2x on the right (since it is smaller, negatives = NONONO), which will give you
x+20=x^2
Now, we take the square root of both sides to get
rad(x+20)=x
Now we have to simplify. 20 doesn't have a square root, but 4 goes into 20, and 4 has a square root of 2. This now becomes
2rad(x+5)
This doesn't simplify any further... we have a problem... no way to isolate x as far as my knowledge goes... Sorry, can't help you any further than that, but another person or your teacher might be able to. R.I.P...
Answer:
4.5 minutes
Step-by-step explanation:
first convert 3/4 to a decimal so you can multiply it which would be .75
so then .75 times 6=
4.5
The missing piece of information in the proof is that m∠DOA and m∠BOC are vertical opposite angles.
<h3>How to find vertically opposite angles?</h3>
We want to prove that m∠BOC = 90°.
We are given that m∠AOB is a right angle triangle. Thus;
m∠BOC must also be equal to 90°
Now, since m∠BOC and m∠AOB are right angles, then it means that we must equally say that m∠DOA and m∠BOC are vertical opposite angles and they are as such equal.
Thus, the missing piece of information in the proof is that m∠DOA and m∠BOC are vertical opposite angles.
Read more about vertical opposite angles at; brainly.com/question/24425517
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Answer:
<h3>96 is the answer. </h3>
Step-by-step explanation:
<h3>The L.C.M of 8 and 12 is 24</h3><h3>The H.C.F of 8 and 12 is 4</h3>
<h3>We multiply </h3><h3>24 *4 we shall get 96 as the answer. </h3><h3 />
Add 72, 75, and 83, which equal 230. Then, since there are three values, you divide the total (230) by 3, which would equal 76.6 (cont), therefore meaning they can only raise their average (using the three tests, from a base grade of 0) to a 76.6 percent (or 77 if teacher rounds grade)
