Answer:
41.13 sq m
Step-by-step explanation:
area of square = 4² = 16
there are two quarter-circles which equals one semicircle
area of semi-circle is πr²/2
A = 4²π/2 = 8π = 25.13
add together: 16 + 25.13 = 41.13
Answer:
They completed 13, 3 credit classes
Step-by-step explanation:
1. Make 2 formulas. In this case: x+y=18
and 3x+4y=59
2. Then multiply x+y=18 by 3 and subtract the two equations.
Find y which is 5 and input into the equations. Then find your answer.
Answer:
6, 0, 10
b
Step-by-step explanation:
Answer:The distance between the lines stays constant, and they never intersect. In other words, you can translate (move) either line by that constant distance, in some direction, to get the other line. It's just like how when you change the y-intercept but keep the slope the same, you get parallel lines.
Step-by-step explanation:
Hope this helps ツ
Answer:
![m \times H=\left[\begin{array}{c c c}\boxed{-9} & \boxed{36} & \boxed{-\dfrac{9}{2}}\end{array}\right]](https://tex.z-dn.net/?f=m%20%5Ctimes%20H%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%20c%20c%7D%5Cboxed%7B-9%7D%20%26%20%5Cboxed%7B36%7D%20%26%20%5Cboxed%7B-%5Cdfrac%7B9%7D%7B2%7D%7D%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
<u>Calculate the value of m</u>
Given:
![3\left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]=\dfrac{2}{3}m \times \left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]](https://tex.z-dn.net/?f=3%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%20c%7D-1%20%26%202%20%5C%5C4%20%26%208%5Cend%7Barray%7D%5Cright%5D%3D%5Cdfrac%7B2%7D%7B3%7Dm%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%20c%7D-1%20%26%202%20%5C%5C4%20%26%208%5Cend%7Barray%7D%5Cright%5D)
Therefore:



<u>Calculate the value of H</u>
Given:
![\left(H+ \left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]\right)+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]=\left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]+\left(\left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]\right)](https://tex.z-dn.net/?f=%5Cleft%28H%2B%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%20c%20c%7D1%20%26%204%20%26%20-2%5Cend%7Barray%7D%5Cright%5D%5Cright%29%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%20c%20c%7D3%20%26%202%20%26%20-6%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%20c%20c%7D-2%20%26%208%20%26%20-1%5Cend%7Barray%7D%5Cright%5D%2B%5Cleft%28%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%20c%20c%7D1%20%26%204%20%26%20-2%5Cend%7Barray%7D%5Cright%5D%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%20c%20c%7D3%20%26%202%20%26%20-6%5Cend%7Barray%7D%5Cright%5D%5Cright%29)
Therefore:
![\implies H= \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]](https://tex.z-dn.net/?f=%5Cimplies%20H%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%20c%20c%7D-2%20%26%208%20%26%20-1%5Cend%7Barray%7D%5Cright%5D)
<u />
<u>Calculating m × H</u>
<u />
<u />![\implies m \times H=\dfrac{9}{2} \times \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]](https://tex.z-dn.net/?f=%5Cimplies%20m%20%5Ctimes%20H%3D%5Cdfrac%7B9%7D%7B2%7D%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%20c%20c%7D-2%20%26%208%20%26%20-1%5Cend%7Barray%7D%5Cright%5D)
<u />![\implies m \times H=\left[\begin{array}{c c c}\dfrac{9}{2}(-2) & \dfrac{9}{2}(8) & \dfrac{9}{2}(-1)\end{array}\right]](https://tex.z-dn.net/?f=%5Cimplies%20m%20%5Ctimes%20H%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%20c%20c%7D%5Cdfrac%7B9%7D%7B2%7D%28-2%29%20%26%20%5Cdfrac%7B9%7D%7B2%7D%288%29%20%26%20%5Cdfrac%7B9%7D%7B2%7D%28-1%29%5Cend%7Barray%7D%5Cright%5D)
<u />