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2 years ago

When a molecule of nad+ gains a hydrogen atom, the molecule becomes reduced.

Chemistry

1 answer:

Ilia_Sergeevich [38]2 years ago

5 0

The answer is true.the molecule becomes reduced.

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Do acids have ph above 7?

nata0808 [166]

No acids have a ph of less than 7 our rain is around a six. dilated water is a 7 and any thing above a 7 is a base

5 0

2 years ago

Read 2 more answers

Would you expect manganese(II) oxide, MnO, to react more readily with HF(aq) or NaOH(aq)?

ella [17]

Answer:

NaOH(aq)

Explanation:

NaOH(aq) is known to precipitate Mn^2+ ions according to the following reaction; Mn^2+(aq)+2OH^−(aq)↽−−⇀Mn(OH)2(s)

Hence, manganese(II) oxide reacts more readily with NaOH(aq) under ordinary conditions precipitating the metal hydroxide solid. This is one of the characteristic reactions of Mn^2+.

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2 years ago

A rigid cylinder of gas shows a pressure of 600 torr at 215 K. It is moved to a new storage site where the pressure is now 750 t

Ronch [10]

PV=nRT

Here
P1/T1= P2 / T2
1 torr=133 pascal
600 *133 /215 = 750 *133 / t2
T2= 268.75 K

5 0

2 years ago

........................................................

masha68 [24]

Answer:

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8 0

2 years ago

an ideal gas is at a pressure 1.00 x 10^5 N/m^2 and occupies a volume 11.00 m^3. If the gass is compressed to a volume of 1.00 m

bogdanovich [222]

Answer:

$P_2=1.1x10^6Pa$

Explanation:

Hello.

In this case, we can solve this problem by applying the Boyle's law which allows us to understand the pressure-volume behavior as a directly proportional relationship:

$P_1V_1=P_2V_2$

In such away, knowing the both the initial pressure and volume and the final volume, we can compute the final pressure as shown below:

$P_2=\frac{P_1V_1}{V_2}$

Consider that the given initial pressure is also equal to Pa:

$P_2=\frac{1.00x10^5Pa*11.00m^3}{1.00m^3}\\ \\P_2=1.1x10^6Pa$

Which stands for a pressure increase when volume decreases.

Regards.

4 0

2 years ago