All categories

3 years ago

Explain the law of conservation of matter using your own examples.

Chemistry

1 answer:

SVETLANKA909090 [29]3 years ago

8 0

matter cannot be created or destroyed

CaCl2 + Na2SO4 ---> CaSO4 +2NaCl

You might be interested in

Which of these could be separated by physical means such as distillation or filtration?

Mama L [17]

Something that can be separated by physical means implies that there is a noticeable difference between the two components when mixed together. For example, salt water has a noticeable difference in that the boiling points of water and salt are so different that the water can be separated by evaporation. The only thing that can be separated by physical means is a mixture.

5 0

4 years ago

How many atoms are there in 3 moles of Fe?

slamgirl [31]

N=N/Na
----. N=nxNa=3x6.023x10^23=1.8069e+24

7 0

3 years ago

Neha and Reha are playing see-saw. Neha is sitting 60 cm away from the fulcrum and Reha is sitting 40 cm away from the fulcrum.

stich3 [128]

Answer:

Reha should apply 540 N to lift Neha.

Explanation:

L = 360 N

LD = 60 m

E =?

ED = 40m

NOW

L * LD = E * ED

360 *60 = E*40

21600/40 = E

540 N = E

4 0

3 years ago

All members of the alkene series of hydrocarbons have the general formula:

LenaWriter [7]

CnH2n since the equivalent unsaturation is equal with 1

7 0

3 years ago

Consider the following reaction: 2CH3OH(g)  2CH4(g) + O2(g) ΔH = +252.8 kJ a) Calculate the amount of heat transferred when 24.

denpristay [2]

Answer:

For a: The amount of heat transferred for the given amount of methanol is 94.6736 kJ.

For b: The mass of methane gas produced will be 10.384 g.

Explanation:

For the given chemical reaction:

$2CH_3OH(g)\rightarrow 2CH_4(g)+O_2(g);\Delta H=+252.8kJ$

For a:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

Given mass of methanol = 24.0 g

Molar mass of methanol = 32.04 g/mol

Putting values in above equation, we get:

$\text{Moles of methanol}=\frac{24.0g}{32.04g/mol}=0.749mol$

By Stoichiometry of the reaction:

For every 2 moles of methanol, the amount of heat transferred is +252.8 kJ.

So, for every 0.749 moles of methanol, the amount of heat transferred will be = $\frac{252.8}{2}\times 0.749=94.6736kJ$

Hence, the amount of heat transferred for the given amount of methanol is 94.6736 kJ.

For b:

By Stoichiometry of the reaction:

252.8 kJ of energy is absorbed when 2 moles of methane gas is produced.

So, 82.1 kJ of energy will be absorbed when = $\frac{2}{252.8}\times 82.1=0.649mol$ of methane gas is produced.

Now, calculating the mass of methane gas from equation 1, we get:

Molar mass of methane gas = 16 g/mol

Moles of methane gas = 0.649 moles

Putting values in equation 1, we get:

$0.649mol=\frac{\text{Mass of methane gas}}{16g/mol}\\\\\text{Mass of methane}=10.384g$

Hence, the mass of methane gas produced will be 10.384 g.

7 0

4 years ago