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Alex
3 years ago
5

I REALLY NEED HELP WITH MY ALEGBRA HOMEWORK!!!!!!!!

Mathematics
1 answer:
mamaluj [8]3 years ago
5 0

Answer:

1. is 55 cans I dont know the fomula but ...

2. the 16th term is 521

3. Hope this help:D

Step-by-step explanation:

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You want to walk from home to a clothing store that is 3/4 miles away. You stop for a rest after 1/2 miles. How much farther do
11Alexandr11 [23.1K]

Answer:

1/4

Step-by-step explanation:

1/2 = 2/4

3/4-2/4=1/4

7 0
3 years ago
The sum of two numbers is -7. Five times the first number plus the second number is 1. What are the numbers?
arlik [135]

Answer:

Step-by-step explanation:

Well you only want the two equations so here they are.

x + y = -7

5*x + y = 1

I should give you the answer.

x = 2

y = -9 I think. These answers were done in my head.

4 0
2 years ago
Is the number a multiple of8?Write yes or no.
Sergeeva-Olga [200]

Answer:

40 and 8 is the only multiple of 8

8x5=. 40

8x1 = 8

7 0
3 years ago
Read 2 more answers
Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a seco
kari74 [83]

Answer:

C. \frac{1}{18}

Step-by-step explanation:

Given: Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl then a second card is drawn.

To Find: If the cards are drawn at random and if the sum of the numbers on the cards is 8, what is the probability that one of the two cards drawn is numbered 5.

Solution:

Sample space for sum of cards when two cards are drawn at random is \{(1,1),(1,2),(1,3)......(6,6)\}

total number of possible cases =36

Sample space when sum of cards is 8 is \{(3,5),(5,3),(6,2),(2,6),(4,4)\}

Total number of possible cases =5

Sample space when one of the cards is 5 is \{(5,3),(3,5)\}

Total number of possible cases =2

Let A be the event that sum of cards is 8

p(\text{A}) =\frac{\text{total cases when sum of cards is 8}}{\text{all possible cases}}

p(\text{A})=\frac{5}{36}

Let B be the event when one of the two cards is 5

probability than one of two cards is 5 when sum of cards is 8

p(\frac{\text{B}}{\text{A}})=\frac{\text{total case when one of the number is 5}}{\text{total case when sum is 8}}

p(\frac{\text{B}}{\text{A}})=\frac{2}{5}

Now,

probability that sum of cards 8 is and one of cards is 5

p(\text{A and B}=p(\text{A})\times p(\frac{\text{B}}{\text{A}})

p(\text{A and B})=\frac{5}{36}\times\frac{2}{5}

p(\text{A and B})=\frac{1}{18}

if sum of cards is 8 then probability that one of the cards is 8 is \frac{1}{18}, option C is correct.

3 0
2 years ago
The scale on a map is 1/4 inch equals 3/4 mile. How long is one mile on the map?
frozen [14]

Answer:it would be 1/16+1/4=1 mile

Step-by-step explanation:

3 0
3 years ago
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