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Mashutka [201]
3 years ago
8

For the following normal distribution, give the x-values of the inflection points of the curve (the points where the curve's con

cavity changes).
x ~ N(0, 52)
Mathematics
1 answer:
3241004551 [841]3 years ago
6 0

Answer:

The x-values of the inflection points of the curve are x = -52 and x = 52.

Step-by-step explanation:

Suppose we have a normal curve with mean \mu and standard deviation \sigma

The x-values of the inflection points of the curve are x = \mu - \sigma and x = \mu + \sigma

x ~ N(0, 52)

This means that \mu = 0, \sigma = 52

So

x = 0 - 52 = -52

x = 0 + 52 = 52

The x-values of the inflection points of the curve are x = -52 and x = 52.

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