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Sophie [7]
3 years ago
6

60.0 g of NH Cl are dissolved in 100 grams of water at 60.0° C. This solution is

Chemistry
1 answer:
Sidana [21]3 years ago
3 0

Answer:

B) is the correct answer

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Select the correct use of the compound tms in nmr spectroscopy.a. it is a signal-to-noise enhancerb. it is an internal standard
SpyIntel [72]

TMS stands for Tetramethylsilane

Formula : Si(CH₃)₄

It is used as internal standard for chemical shift

In TMS all the four methyl groups are similar thus all the 12 hydrogen are chemically equivalent. They will show proton NMR at same level and which will appear as a singlet.

We have defined this singlet to be as reference set as zero.

Generally the other organic compounds show chemical shift downfield.So have positive chemical shift with respect to TMS shift.

8 0
3 years ago
All the chemical ingredients to make slime have a mass of 48 grams after we mix all the ingredients together how much mass will
Alborosie

Answer:

The answer is C. 48 grams

Explanation: If the mass of all the ingredients is 48 grams the that would be your in total answer

5 0
3 years ago
Change the given word equation into balanced equation <br><br>Hydrogen+Chloride=Hydrogen chloride​
nirvana33 [79]

Answer:

h2 +2cl -> 2hcl

Explanation:

h2 + cl -> HCl

h2 +2cl -> 2hcl

3 0
4 years ago
What happens when naoh is added to a buffer composed of ch3cooh and ch3coo−?
BartSMP [9]
Hello!

When NaOH is added to a buffer composed of CH₃COOH and CH₃COO⁻, the following reactions happen:

-First, the NaOH is neutralized by CH₃COOH:

NaOH + CH₃COOH → H₂O + CH₃COONa

-Second, the CH₃COONa dissociates in its ions:

CH₃COONa  → CH₃COO⁻ + Na⁺

-Finally, CH₃COO⁻ (a weak base) reacts with water to form OH⁻ ions and regenerate CH₃COOH

CH₃COO⁻ + H₂O ⇄ CH₃COOH + OH⁻

By this sequence of reactions, the buffer can mitigate the effect of the strong base added.

Have a nice day!
7 0
3 years ago
Read 2 more answers
1. How much NaCl would you need to weigh out to prepare 100 mL of a 2.5% NaCl<br> solution?
Ira Lisetskai [31]
<h3><u>Answer</u> - 5.85g</h3>

<h3><u>Solution</u> - </h3>

Using the concentration equation, m = CVMo where m is the mass of solute, C is the concentration (M), V is the volume of solution (L) and Mo is molar mass of the solute (g):

Given,

Molar mass of NaCl, M = 58.5g/mol

Volume of the solution, V= 100ml = 0.1L

Molarity, S= 1M

Mass of the solute,W=?

W=SMV

= 1×58.5×0.1

= 5.85g

7 0
2 years ago
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