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3 years ago

60.0 g of NH Cl are dissolved in 100 grams of water at 60.0° C. This solution is

Chemistry

1 answer:

Sidana [21]3 years ago

3 0

Answer:

B) is the correct answer

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What is formed when sediment is blown against an obstacle and settles behind it

Naddik [55]

The answer should be "Dunes"

4 0

3 years ago

The following reaction was carried out in a 3.00 L reaction vessel at 1100 K:

Nady [450]

Answer:

$Q=0.840$

Explanation:

Hello,

In this case, since the given undergoing chemical reaction is correctly balanced, the reaction quotient is computed as well as the equilibrium constant but in terms of the given concentrations that are:

$C_{C}=\frac{5.25mol}{3.00L} =1.75M\\C_{H_2O}=\frac{12.2mol}{3.00L} =4.07M\\C_{CO}=\frac{3.90mol}{3.00L}=1.30M\\C_{H_2}=\frac{7.90mol}{3.00L} =2.63M$

In such a way, the reaction quotient turns out:

$Q=\frac{C_{CO}C_{H_2}}{C_{H_2O}}=\frac{1.30M*2.63M}{4.07M}\\ Q=0.840$

Taking into account that carbon is not included since it is solid.

Best regards.

7 0

3 years ago

Write the name and the symbol of the element that fits each of the following descriptions: a) the alkaline earth metal in the si

brilliants [131]

Explanation:

a) Barium

b) The metalloid in third period is Silicon

c) Group 4A (or IVA) of the periodic table includes the nonmetal carbon (C)

d) At this temperature, fluorine and chlorine are gases, bromine is a liquid, and iodine and astatine are solids.

e) osmium

f) chlorine (Cl, element 17) are a gas at room temperature, and is found as diatomic molecule (Cl2).

8 0

3 years ago

Aluminum oxide was prepared by heating 225 g of chromium (III) oxide with 125 g of aluminum. Calculate the percent yield of 100.

Veronika [31]

Answer:

66.25%

Explanation:

4 0

4 years ago

1.42 mol sample of neon gas at a temperature of 13.0 °C is found to occupy a volume of 25.5 liters. The pressure of this gas sam

Dima020 [189]

Answer: 996 mmHg

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

According to the ideal gas equation:

$PV=nRT$

P = Pressure of the gas = ?

V= Volume of the gas = 25.5 L

T= Temperature of the gas = 13°C = (273+13) K = 286K

R= Gas constant = 0.0821 atmL/K mol

n= moles of gas= 1.42

$P=\frac{nRT}{V}=\frac{1.42\times 0.0821\times 286}{25.5}=1.31atm=996mmHg$ (760mmHg=1atm)

Thus pressure of this gas sample is 996 mm Hg.

3 0

3 years ago