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Svetach [21]
3 years ago
6

Which equation describes a parabola that opens up or down and whose vertex is at the point (h,v)

Mathematics
1 answer:
Serggg [28]3 years ago
7 0

y  = a ( x - h)^2 + v             


a is positive when the parabola opens up  and negative when it opens down.
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If 3 3/4 lb of candy costs 20 .25 how many would 1 lb of candy cost
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solution:

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3 0
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3 years ago
Read 2 more answers
Given a polynomial f(x), if (x + 5) is a factor, what else must be true?
PolarNik [594]
Rule: If x-k is a factor of p(x), then p(k) = 0. This is a special case of the remainder theorem.

Using that rule, we can see that x+5 is really x-(-5) so k = -5. 

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4 0
3 years ago
Complete the table of values for this absolute value function. Then use the drawing tool(s) to graph the function. F(x)-2|x+1|-1
rusak2 [61]

Answer:

Please check the explanation!

Step-by-step explanation:

Given the equation

f\left(x\right)=-2|x+1|-1

As some of the absolute rules are:

  • \left|a\right|=a,\:a\ge 0
  • \:|-a|=a,\:\quad \:a>0

NOW, let us solve!

Let us substitute all the table values

Putting x = -4

y=-2\left|-4+1\right|-1        ∵\mathrm{Apply\:absolute\:rule}:\quad \left|a\right|=a,\:a\ge 0

y=-6-1

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Putting x = -3

y=-2|-3+1|-1\:

y=-4-1

y=-5

when x = -3, then y = -5

Putting x = -2

y=-2\left|-2+1\right|-1

y=-2-1

y=-3

when x = -2, then y = -3

Putting x = -1

y=-2\left|-1+1\right|-1

y=-0-1

y=-1

when x = -1, then y = -1

Putting x = 0

y=-2\left|0+1\right|-1

y=-2-1

y=-3

when x = 0, then y = -3

Putting x = 1

y=-2\left|1+1\right|-1

y=-4-1

y=-5

when x = 1, then y = -5

The graph is also attached below.

6 0
3 years ago
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