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GarryVolchara [31]
3 years ago
15

Rewrite the equation 6x + 7y = 14 into slope-intercept form (y = mx + b)

Mathematics
2 answers:
Tamiku [17]3 years ago
6 0

rearrange into the form y = mx + b

subtract 6x from both sides of the equation

7y = - 6x + 14

divide all terms by 7

y = - \frac{6}{7} x + 2 → in slope- intercept form


AfilCa [17]3 years ago
6 0

Answer : The slope-intercept form of give equation is, y=-\frac{6}{7}x+2

Step-by-step explanation :

As we know that the slope-intercept form is:

y = mx + b

where,

m and b are the real numbers and y and x are intercepts.

m represent the slope of a line.

As we are given the expression of equation.

6x + 7y = 14

Now rearranging the equation according to the slope-intercept form, we get:

7y=-6x+14

y=-\frac{6}{7}x+\frac{14}{7}

y=-\frac{6}{7}x+2

Thus, the slope-intercept form of give equation is, y=-\frac{6}{7}x+2

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Answer:

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A)The volume of a cube, as all sides are equal:

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2 years ago
The time needed to complete a final examination in a particular college course is normally distributed with a mean of 77 minutes
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Answer:

a. The probability of completing the exam in one hour or less is 0.0783

b. The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is 0.3555

c. The number of students will be unable to complete the exam in the allotted time is 8

Step-by-step explanation:

a. According to the given we have the following:

The time for completing the final exam in a particular college is distributed normally with mean (μ) is 77 minutes and standard deviation (σ) is 12 minutes

Hence, For X = 60, the Z- scores is obtained as follows:

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Using the standard normal table, the probability P(Z≤−1.4167) is approximately 0.0783.

P(Z≤−1.4167)=0.0783

Therefore, The probability of completing the exam in one hour or less is 0.0783.

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Z=  X−μ /σ

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Using the standard normal table, the probability P(Z≤−0.1667) is approximately 0.4338.

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P(60<X<75)=P(Z≤−0.1667)−P(Z≤−1.4167)

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=0.3555

​

Therefore, The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is 0.3555

c. In order to compute  how many students you expect will be unable to complete the exam in the allotted time we have to first compute the Z−score of the critical value (X=90) as follows:

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UsING the standard normal table, the probability P(Z≤1.0833) is approximately 0.8599.

Therefore P(Z>1.0833)=1−P(Z≤1.0833)

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​

Therefore, The number of students will be unable to complete the exam in the allotted time is= 60×0.1401=8.406

The number of students will be unable to complete the exam in the allotted time is 8

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