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choli [55]
2 years ago
9

Suppose that a baseball is tossed up into the air at an initial velocity 1818​​\text{ m/s} m/s​. The height of the baseball at t

ime tt​ in seconds is given by h\mathopen{}\mathclose{\left(t\right)}=18 t-4.9 t^{2}h(t)=18t−4.9t 2 ​​​​​ (in meters). a) What is the average velocity for \left[1, 1.5\right][1,1.5]​?
Physics
1 answer:
olga2289 [7]2 years ago
5 0

Answer:

13.1 m/s

Explanation:

Given that a baseball is tossed up into the air at an initial velocity 18 m/s​. The height of the baseball at time t​ in seconds is given by h(t) = 18t−4.9t 2 ​​​​​ (in meters).

a) What is the average velocity for [1,1.5]​?

To calculate the velocity travelled by the ball, differentiate the function.

dh/dt = 18 - 9.8t

Substitute t for 1 in the above Differential function

dh/dt = 18 - 9.8 (1)

But dh/dt = velocity

V = 18 - 9.8

V = 8.2 m/s

Average velocity = ( U + V ) / 2

Average velocity = (18 + 8.2)/2

Average velocity = 26.2/2

Average velocity = 13.1 m/s

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stepladder [879]

Answer:

1. A1, B2, C3

2. 47.1°

Explanation:

Sum of forces in the x direction:

∑Fₓ = ma

f − Fᵥᵥ = 0

f = Fᵥᵥ

Sum of forces in the y direction:

∑Fᵧ = ma

N − W = 0

N = W

Sum of moments about the base of the ladder:

∑τ = Iα

Fᵥᵥ h − W (b/2) = 0

Fᵥᵥ h = ½ W b

Fᵥᵥ (l sin θ) = ½ W (l cos θ)

l Fᵥᵥ sin θ = ½ l W cos θ

The correct set of equations is A1, B2, C3.

At the smallest angle θ, f = Nμ.  Substituting into the first equation, we get:

Nμ = Fᵥᵥ

Substituting the second equation into this equation, we get:

Wμ = Fᵥᵥ

Substituting this into the third equation, we get:

l (Wμ) sin θ = ½ l W cos θ

μ sin θ = ½ cos θ

tan θ = 1 / (2μ)

θ = atan(1 / (2μ))

θ = atan(1 / (2 × 0.464))

θ ≈ 47.1°

5 0
3 years ago
. If the centripetal and thus frictional force between the tires and the roadbed of a car moving in a circular
mel-nik [20]
<span>In this particular case, where car is moving through curvature, so it is moving in circular motion, force acting on car is centripetal force which holds car not to fly out. Centripetal force is always pointed in the middle of circle. Here frictional force has role of centripetal force. If frictional force is to weak, car would fly out of curvutare.</span>
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2 years ago
Motion equation of object is
Ganezh [65]

Take the derivative to find the velocity of the object:

v=\dfrac{\mathrm dx}{\mathrm dt}=-12+6t

The object stops when v=0:

-12+6t=0\implies6t=12\implies t=2

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3 years ago
HELP FAST!!!!!!!
Alex17521 [72]

<u>Answer</u>

A. Metals A and metals B



<u>Explanation</u>

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In our case, heat transfer will take place in all four metals.

Metal A will transfer heat to the water since it's temperature is higher than that of water.

Metal B will also transfer heat to the water since it's temperature is higher than that of water.

Metal C will get heat from the water since it's colder than the water.

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7 0
3 years ago
Read 2 more answers
During the first 14 minutes of a 1.0 hour trip, a car has an average speed 36 km/h. What must the average speed in km/h of the c
oksian1 [2.3K]

Answer:

85.5 km/h

Explanation:

t_{1} = time interval for first phase = 14 min = \frac{14}{60} h = 0.233 h

t_{2} = time interval for second phase = 46 min = \frac{46}{60} h = 0.767 h

v = average speed for the entire trip = 74 km/h

v_{1} = average speed in first phase = 36 km/h

v_{2} = average speed in second phase

d_{1} = distance traveled in first phase

d_{2} = distance traveled in first phase

average speed is given as

v = \frac{d_{1} + d_{2}}{t_{1} + t_{2}}

v = \frac{v_{1} t_{1} + v_{2} t_{2}}{t_{1} + t_{2}}

74 = \frac{(36) (0.233) + v_{2} (0.767)}{0.233 + 0.767}

74 = (36) (0.233) + v_{2} (0.767)

v_{2} = 85.5 km/h

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3 years ago
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