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3 years ago

Can somebody help me with this ?? :)

Mathematics

1 answer:

astra-53 [7]3 years ago

4 0

The answer would be A

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When randomly choosing two cards from a standard deck of cards without replacement, what is the probability of choosing a face c

Radda [10]

There are 12 face cards and 4 aces to choose from. For the first card, the probability of drawing a face is $\dfrac{\binom{12}1}{\binom{52}1}=\dfrac{12}{52}$ . Then the probability of drawing an ace second is $\dfrac{\binom41}{\binom{51}1}=\dfrac4{51}$ .

So the probability of drawing these two particular cards in the given order is

$\dfrac{12}{52}\cdot\dfrac4{51}=\dfrac4{221}$

4 0

3 years ago

A person runs 1 4 of a mile in 1 32 of an hour. Compute the unit rate by setting up a complex fraction and simplifying.

ycow [4]

1/4 mile in 1/32 hr
unit rate would be x miles in 1 hour.
A complex fraction is a fraction that has a fraction in the numerator OR denominator OR both.

(1/4) / (1/32) =(1/4) * (32/1) = 8 miles in 1 hour

6 0

3 years ago

Read 2 more answers

The population of rabbits on an island is growing exponentially. In the year 1990, the population of rabbits was 1200, and by 19

kobusy [5.1K]

Answer:

2023 rabbits

Step-by-step explanation:

The exponential model consists of the following expression:

$y = A \cdot r^{t}$

Where:

$A$ - Initial population.

$r$ - Increase rate.

$t$ - Time

$y$ - Current population.

The initial population and increase rate are, respectively:

$1200 = A \cdot r^{0}$

$A = 1200$

$1700 = 1200 \cdot r^{4}$

$r^{4} = \frac{1700}{1200}$

$r^{4} = \frac{17}{12}$

$r = \sqrt[4]{\frac{17}{12} }$

$r \approx 1.091$

The exponential model that predicts the population of rabbits is:

$y = 1200\cdot 1.091^{t}$

Lastly, the expected population for the year 1996 is:

$y = 1200\cdot 1.091^{6}$

$y\approx 2023.624\,rabbits$

5 0

3 years ago

If figure 1 is 3 then what is figure 100th

Alexxx [7]

A) 3x100= 300 since figure 1 is 3 then figure 100 is 3x100

8 0

3 years ago

What is the value of x?

frez [133]

$\left\{\begin{array}{ccc}x+2y=4&\text{multiply both sides by 5}\\4x-5y=42&\text{multiply both sides by 2}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}5x+10y=20\\8x-10y=84\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad13x=104\qquad\text{divide both sides by 13}\\\\\boxed{x=8}\\\\Answer:\ \boxed{\boxed{x=8}}$

5 0

2 years ago