S=-1 see attachment for explanation
Answer:
60 minutes for the larger hose to fill the swimming pool by itself
Step-by-step explanation:
It is given that,
Working together, it takes two different sized hoses 20 minutes to fill a small swimming pool.
takes 30 minutes for the larger hose to fill the swimming pool by itself
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
<u>To find LCM of 20 and 30</u>
LCM (20, 30) = 60
<u>To find the efficiency </u>
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
x = 60/30 =2
x + y = 60 /20 = 3
Therefore efficiency of y = (x + y) - x =3 - 2 = 1
so, time taken to fill the swimming pool by small hose = 60/1 = 60 minutes
Answer:
y = -14/3x + 43/3
Step-by-step explanation:
y2 - y1 / x2 - x1
5 - (-9) / 2 - 5
14 / -3
- 14/3
y = -14/3x + b
5 = -14/3(2) + b
5 = -28/3 + b
43/3 = b
y = -14/3x + 43/3
A. 35% decrease yearly
B. 267.75
C. How much the computer is worth after 4 years
