<span>The triangle on paper is 5 inches wide by 7 inches high.</span><span>
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If 1 inch on paper is equal to 1.5 feet on paper, then you need to multiply all dimensions by 18 because 1.5 feet is equal to 18 inches and you are getting 18 inches on the real banner for every inch on the paper banner. </span><span>
5 * 18 = 90 inches from the base of the rear triangle.</span><span>
7 * 18 = 125 inches for the height of the rear triangle. </span><span>
</span><span>The area of the paper triangle will be 5 * 7 / 2 = 35/2 square inches.</span><span>
The area of the rear triangle will be 90 * 125 / 2 = 5625 square inches. </span><span>
regarding feet:
The base of the real banner will be 125/12 = 10.41666666....... feet.</span><span>
the height of the real banner will be 90 / 12 = 7.5 feet.</span><span>
the area of the real banner will be 5625 / 12^1 = 5625 / 144 = 39.0625 square feet.</span><span>
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Es la segunda media es 1.65, mediana es 1.65, y modo es 1.61
The IQR is q1-q3! Put the numbers in order, least to greatest. then find the quartiles.
Answer:
x = 35
Step-by-step explanation:
Solve for x:
6 x - 15 = 4 x + 55
Hint: | Move terms with x to the left hand side.
Subtract 4 x from both sides:
(6 x - 4 x) - 15 = (4 x - 4 x) + 55
Hint: | Combine like terms in 6 x - 4 x.
6 x - 4 x = 2 x:
2 x - 15 = (4 x - 4 x) + 55
Hint: | Look for the difference of two identical terms.
4 x - 4 x = 0:
2 x - 15 = 55
Hint: | Isolate terms with x to the left hand side.
Add 15 to both sides:
2 x + (15 - 15) = 15 + 55
Hint: | Look for the difference of two identical terms.
15 - 15 = 0:
2 x = 55 + 15
Hint: | Evaluate 55 + 15.
55 + 15 = 70:
2 x = 70
Hint: | Divide both sides by a constant to simplify the equation.
Divide both sides of 2 x = 70 by 2:
(2 x)/2 = 70/2
Hint: | Any nonzero number divided by itself is one.
2/2 = 1:
x = 70/2
Hint: | Reduce 70/2 to lowest terms. Start by finding the GCD of 70 and 2.
The gcd of 70 and 2 is 2, so 70/2 = (2×35)/(2×1) = 2/2×35 = 35:
Answer: x = 35
7x20x11= 1540
30x4x11=1320
1540+1320=2860
