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3 years ago

PLEASE HELP!!!!! The table below shows the volume of two samples, X and Y, when placed in three containers of different volumes.

Chemistry

1 answer:

Dahasolnce [82]3 years ago

7 0

Answer:

B m8

Explanation:

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La masse et volume. S'il vous plaît repondre aux questions 2, 3, et 4.

ella [17]

Answer:

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Explanation:

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3 years ago

A molecule of composition is replicated in a solution containing unlabeled (not radioactive) GTP, CTP, and TTP plus adenine nucl

Lapatulllka [165]

Answer:

Please find the complete question in the attached file.

Explanation:

It would only be radioactive if the DNA molecule that employed the poly-T rand as templates. Its other molecule of the daughter would not have been radioactive as it did not need dATP for its replication. While each strand of the second molecule includes t, simultaneous reproduction dATP from both daughter molecules is needed so that each of those is radioactive.

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3 years ago

A state function represent?

jeyben [28]

Answer:

a property whose value does not depend on the path taken to reach that specific value.

Explanation:

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3 years ago

Consider a solution that is 0.05 M HCl. Your goal is to neutralize 1 L of this solution (i.e. bring the pH to 7). You also have

Ilia_Sergeevich [38]

Answer:

The volume of NaOH required is - 0.01 L

Explanation:

At equivalence point ,

Moles of $HCl$ = Moles of NaOH

Considering :-

$Molarity_{HCl}\times Volume_{HCl}=Molarity_{NaOH}\times Volume_{NaOH}$

Given that:

$Molarity_{NaOH}=5\ M$

$Volume_{NaOH}=?\ L$

$Volume_{HCl}=1\ L$

$Molarity_{HCl}=0.05\ M$

So,

$Molarity_{HCl}\times Volume_{HCl}=Molarity_{NaOH}\times Volume_{NaOH}$

$0.05\times 1=5\times Volume_{NaOH}$

$Volume_{NaOH}=\frac{0.05\times 1}{5}=0.01\ L$

<u>The volume of NaOH required is - 0.01 L</u>

3 0

3 years ago

What is the empirical formula for a compound that is 31.9% potassium, 28.9% chlorine, and 39.2% oxygen?

notsponge [240]

The empirical formula for a compound is KClO3

Explanation
find the moles of each element
moles = % composition/molar mass

molar mass of of potassium =39g/mol ,chlorine = 35.5 g/mol, oxygen =16 g/mol

moles of potassium = 31.9 / 39 = 0.818 moles
moles of chlorine = 28.9/35.5 = 0.814 moles
moles of oxygen = 39.2/ 16 = 2.45 moles

find the mole ratio by dividing with the smallest mole = 0.814 moles

potassium = 0.818/0.814 =1
chlorine = 0.814/0.814 = 1
oxygen = 2.45 /0.814 =3

the empirical formula is therefore = KClO3

7 0

4 years ago