Answer:
2.92 mol
Explanation:
Step 1: Write the balanced equation
2 B(s) + 6 HCI(aq) ⇒ 2 BCl₃(aq) + 3 H₂(g)
Step 2: Establish the appropriate molar ratio
The molar ratio of hydrochloric acid to boron chloride is 6:2.
Step 3: Calculate the moles of boron chloride produced from 8.752 moles of hydrochloric acid
![8.752molHCl \times \frac{2molBCl_3}{6molHCl} = 2.92molBCl_3](https://tex.z-dn.net/?f=8.752molHCl%20%5Ctimes%20%5Cfrac%7B2molBCl_3%7D%7B6molHCl%7D%20%3D%202.92molBCl_3)
Answer : The specific heat of tungsten is, ![0.139J/g^oC](https://tex.z-dn.net/?f=0.139J%2Fg%5EoC)
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
![q_1=-q_2](https://tex.z-dn.net/?f=q_1%3D-q_2)
![m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_f-T_1%29%3D-m_2%5Ctimes%20c_2%5Ctimes%20%28T_f-T_2%29)
where,
= specific heat of tungsten = ?
= specific heat of water = ![4.18J/g^oC](https://tex.z-dn.net/?f=4.18J%2Fg%5EoC)
= mass of tungsten = 19.5 g
= mass of water = 78.5 g
= final temperature = ![23.20^oC](https://tex.z-dn.net/?f=23.20%5EoC)
= initial temperature of tungsten = ![97.80^oC](https://tex.z-dn.net/?f=97.80%5EoC)
= initial temperature of water = ![22.58^oC](https://tex.z-dn.net/?f=22.58%5EoC)
Now put all the given values in the above formula, we get
![19.5g\times c_1\times (23.20-97.80)^oC=-78.5g\times 4.18J/g^oC\times (23.20-22.58)^oC](https://tex.z-dn.net/?f=19.5g%5Ctimes%20c_1%5Ctimes%20%2823.20-97.80%29%5EoC%3D-78.5g%5Ctimes%204.18J%2Fg%5EoC%5Ctimes%20%2823.20-22.58%29%5EoC)
![c_1=0.139J/g^oC](https://tex.z-dn.net/?f=c_1%3D0.139J%2Fg%5EoC)
Therefore, the specific heat of tungsten is, ![0.139J/g^oC](https://tex.z-dn.net/?f=0.139J%2Fg%5EoC)
Its nitrogen as its outer electron is closer to the nucleus so there will be a stronger electrostatic attraction between it and its nucleus
hope that helps
All I have to say is karma