1 mol Au ---------------- 196.9665 g
0.150 mol Au ----------- ?
0.150 x 196.9665 / 1
= 29.54 g
hope this helps!
I would help if i could im sorry im sure someone else will answer soon im honestly trying to help as many people as i can
Image result for non-examples of weather fronts.
Many fronts cause weather events such as rain, thunderstorms, gusty winds, and tornadoes. At a cold front, there may be dramatic thunderstorms. At a warm front, there may be low stratus clouds. Usually, the skies clear once the front has passed.
Answer:
7.5 M
Explanation:
In order to find a solution's molar concentration, or molarity, you need to determine how many moles of solute, which in your case is sodium sulfate,
Na
2
SO
4
, you get in one liter of solution.
That is how molarity was defined -- the number of moles of solute in one liter of solution.
So, you know that you have
0.090
moles of solute in
12 mL
of solution. Your goal here will be to scale up this solution by using this information as a conversion factor to help you determine the number of moles of solute present in
Answer:
2.11x10^26 atoms in 350.8 moles of Aluminum
Explanation:
I converted moles to atoms by using Avogadro's number which is 6.022x10^23
The solution is:
350.8 moles of Al x (6.022x10^23/1 mole) = 2.11x10^26 atoms
