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Phantasy [73]
3 years ago
15

Please help! Don’t know if I’m right!!

Chemistry
1 answer:
kompoz [17]3 years ago
4 0

Answer:e

Explanation:

Bananas

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What is the answer? show proof I will report you if you answer for the points​
IceJOKER [234]

Answer:

A

Explanation:

carbon dioxide is released in cellular respiration

3 0
2 years ago
Jill is making lemonade. She mixes together some water, lemon juice, and sugar. The lemonade is classified as a(n) _________. A)
PolarNik [594]

Hello, Thanks for making your post on brainly!

I would say the best answer is C)Mixture

A mixer is made by combining 2 or more elements, but your not making a new element. And there are no chemical reactions happening to make a new element.

Hope this helps. Have a great day.

8 0
2 years ago
Read 2 more answers
Cl2(g) + 2kBr(s) ---> 2KCl(s) + Br2(g) Rewrite the equation and write the color of each chemical under its name. 2. What type
kolezko [41]

Answer:

Cl2(g) (green/yellow mix) + 2KBr(s) (white) ---> 2KCl(s) (violet) + Br2(g) (reddish brown)

This chemical reaction is a redox type.

Explanation:

Look at the oxidation state, when the number increase your element gets oxidated, when the number decrease, the elements it's getting reduced.

8 0
2 years ago
I need help please ​
Alex17521 [72]

Answer: If you think about it, B. would be the most reasonable answer with the given factors.

4 0
2 years ago
A trial of this decomposition experiment, using different quantities of reactants than those listed in the question above produc
Paul [167]

Answer : The volume of O_2(g) produced at standard conditions of temperature and pressure is 0.2422 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of O_2 gas = (740-22.4) torr = 717.6 torr

P_2 = final pressure of O_2 gas at STP= 760 torr

V_1 = initial volume of O_2 gas = 280 mL

V_2 = final volume of O_2 gas at STP = ?

T_1 = initial temperature of O_2 gas = 25^oC=273+25=298K

T_2 = final temperature of O_2 gas = 0^oC=273+0=273K

Now put all the given values in the above equation, we get:

\frac{717.6torr\times 280mL}{298K}=\frac{760torr\times V_2}{273K}

V_2=242.2mL=0.2422L

Therefore, the volume of O_2(g) produced at standard conditions of temperature and pressure is 0.2422 L

5 0
3 years ago
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