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barxatty [35]
3 years ago
8

Which equation represents the line that passes through (–8, 11) and (4,7/2 )? y =-5/8 x + 6 y = -5/8x + 16 y = -15/2x – 49 y = -

15/2x + 71
Mathematics
1 answer:
White raven [17]3 years ago
3 0
(-8,11)(4,7/2)
slope(m) = (7/2 - 11) / (4 - (-8) = (7/2 - 22/2) / (4 + 8) = (-15/2) / 12 = -15/2 * 1/12 = -15/24 = -5/8

y = mx + b
slope(m) = -5/8
use either of ur points...(-8,11)...x = -8 and y = 11
now we sub and find b, the y int
11 = -5/8(-8) + b
11 = 5 + b
11 - 5 = b
6 = b

so ur equation is : y = -5/8x + 6
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What is the slope-intercept form of the equation of the line perpendicular to y = -x + 10 and passing throught the point (-2,7)?
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Answer:

The slope-intercept form equation of the line perpendicular to y =  -\frac{1}{2} x + 10 and passes through point (-2, 7) is y = 2x + 11 ⇒ Not in the choices

Step-by-step explanation:

The slope-intercept form of the linear equation is y = m x + b, where

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  • b is the y-intercept

The product of the slopes of the perpendicular lines is -1, if the slope of one is m, then the slope of the other is -\frac{1}{m}

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∵ The equation of the given line is y = -\frac{1}{2} x + 10

→ Compare it with the form of the equation above

∴ m =  -\frac{1}{2}

→ Reciprocal it and change its sign to get the slope of the ⊥ line

∴ m⊥ = 2

→ Substitute in the form of the equation above

∴ y = 2x + b

→ To find b substitute x and y in the equation by the coordinates of

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∵ The line passes through the point (-2, 7)

∴ x = -2 and y = 7

∵ 7 = 2(-2) + b

∴ 7 = -4 + b

→ Add 4 to both sides to find b

∵ 7 + 4 = -4 + 4 + b

∴ 11 = b

→ Substitute it in the equation

∴ y = 2x + 11

The slope-intercept form equation of the line perpendicular to y =  -\frac{1}{2} x + 10 and passes through point (-2, 7) is y = 2x + 11

<u><em>Note:</em></u> The answer is not in the choices

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Can y’all help me find the slope
vitfil [10]

Answer:

Step-by-step explanation:

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3 years ago
Read 2 more answers
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