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bazaltina [42]
3 years ago
5

Please help me!! thank you so much!!​

Chemistry
1 answer:
Elis [28]3 years ago
4 0

Answer:

13.75

Explanation:

gets halved every 8 days so halved twice

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Suggest a method for measuring the size of the colony.
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Answer:

Counting the number of colonies that arise on a pour plate can calculate the concentration by multiplying the count by the volume spread on the pour plate. Direct counting methods are easy to perform and do not require highly specialized equipment, but are often slower than other methods

Explanation:

I hope it will help you

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Which body in our solar system has magnetic pole reversals?
sesenic [268]

the correct answer would be the sun

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How does this look? (Its for a science project about animal life
konstantin123 [22]

Answer:

why is there a cherry on its head?

Explanation:

You may want to add details/description to the photo as it is a little confusing

3 0
3 years ago
Read 2 more answers
10.0 g of calcium carbonate was heated. The mass of calcium oxide left was 5.6 g. Calculate the mass of
Kipish [7]

Answer:

4.4g

Explanation:

Mass of CaCO3 = 10g

Mass of CaO = 5.6g

Mass of CO2 =?

Mass of CaCO3 = Mass of CaO + Mass of CO2

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Mass of CO2 = 4.4g

4 0
3 years ago
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Consider the reaction 2 S + 3 O2 → 2 SO3 , which has a 75.1% yield. How much O2 is consumed if 583 g of SO3 are produced?
Ymorist [56]

Answer:

A/1.      10.9 mol O2

Explanation:

583 g x 1 mol SO3 x 3 mol O2 /

      80.057 g mol SO3 x 2 mol SO3

- You just need to find molar mass of SO3, which is 80.057 g.

- Everything else came from formula. Further explanation...

- Always start with what they give, such as 583 g. Then find 1 mol of what is being produced, in this it is SO3. We already found this because we did molar mass above. Next. find how many moles of what they want, which is O2. Look in equation and you can see 3 mol in from of O2. Next, do the same for SO3 and you can find 3 mol in front of that. Lastly, just do the math.

- If you need a further explanation or more help on any problems I would be happy to help, just let me know.

4 0
3 years ago
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