When air descends it compresses. When the air compresses the molecules in the air knock into each other more often, increasing the tempertature.
Hope this helps
Answer:
(a): 2ZnO(s) -----------> 2Zn(s) + O2(g)
2C(s) + O2(g) ---------> 2CO(g)
(b): ZnO(s) + C(s) ---------> Zn(s) + CO(g)
Answer: 2.17mol/L
Explanation:
C=n/V
n: 0.217mol
V: 100.0mL
1. Convert mL to L (100.0mL/1000 = 0.01L)
2. Put numbers into equation (C= 0.217/0.01L)
3. Molarity is 2.17mol/L
First, we calculate of the concentration of the H+ ions in the solution from the pH given. Then, calculate the new concentration after dilution. Calculation are as follows:
pH = -log[H+]
5 = -log[H+]
[H+] = 1 x 10^-5 M
M1V1 = M2V2
<span>1 x 10^-5 M (V1) = M2(100V1)
</span>M2 = 1 x 10^-7
pH = -log[<span>1 x 10^-7</span>]
pH = 7
According to Diagram B, look at the 1600 elevation until you see the descending air line touches it. Then look down at the temperature at the bottom of the graph. It is between 0 degrees to 5 degrees.
The only number that is between that range is 2 degrees C.
