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3 years ago

Is it possible to change the strength of an acid? Explain how you would do this.

Chemistry

1 answer:

Verdich [7]3 years ago

4 0

Answer:

Reducing or increasing the amount of H+ ions / hydronium (H3O+) ions

Explanation:

To reduce the pH (reducing the strength of the acid) can be done by adding a base (including a conjugate base such as bicarbonate ion) which will absorb the H+ ions either through adsorption or reaction.

Adding more H+ decreases the pH of the acid making it stronger. This can be done by adding HCL that will dissociate and increase the H+ ions.

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Zina [86]

Answer:

Explanation:

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3 years ago

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How many elements are in the second group? (column)

zavuch27 [327]

Of the periodic table?

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3 years ago

When 4.41g of phosphoric acid (H3PO4) react with 9.25g of barium hydroxide, water and insoluble barium phosphate form. [T/I-7] a

AnnZ [28]

Answer:

2 H₃PO₄(aq) + 3 Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + 6 H₂O(l)

Explanation:

Let's consider the unbalanced equation that occurs when phosphoric acid reacts with barium hydroxide to form water and barium phosphate. This is a neutralization reaction.

H₃PO₄(aq) + Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + H₂O(l)

We will balance it using the trial and error method.

First, we will balance Ba atoms by multiplying Ba(OH)₂ by 3 and P atoms by multiplying H₃PO₄ by 2.

2 H₃PO₄(aq) + 3 Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + H₂O(l)

Finally, we will get the balanced equation by multiplying H₂O by 6.

2 H₃PO₄(aq) + 3 Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + 6 H₂O(l)

3 0

3 years ago

Helium gas in a cylinder is under 1.12atm pressure at 25.0C. What will be the pressure if the temperature increases to 37.0C?

Irina18 [472]

Answer:

$p_2=1.17atm$

Explanation:

Hello!

In this case, considering that the Gay-Lussac's law allows us to relate the temperature-pressure problems as directly proportional relationships:

$\frac{p_2}{T_2} =\frac{p_1}{T_1} \\\\$

Thus, for the initial pressure and temperature in kelvins the final temperature in kelvins, we compute the final pressure as:

$p_2=\frac{p_1T_2}{T_1} \\\\p_2=\frac{1.12atm*310.15K}{298.15K}\\\\p_2=1.17atm$

Best regards!

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3 years ago

CaCo3+2HCL Cacl2+h2o+co2

Rasek [7]

Answer:

Here

Explanation:

This is an acid-base reaction (neutralization): CaCO3 is a base, HCl is an acid.

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3 years ago