The area of a parking lot is 805 square meters. A car requires 5 meters and a bus requires 32 square meters of space. There can
be at most 80 vehicles parked at one time. If the cost to park a car is $2.00 and a bus is $6.00, how many should be in the lot to maximize income?
1 answer:
Answer:
80 cars will maximize revenue
Step-by-step explanation:
The revenue per square meter for parked cars is ...
$2.00/5 = $0.40
The revenue per square meter for buses is ...
$6.00/32 = $0.1875
Thus the available space should be used to park the maximum number of cars.
80 cars should be in the lot to maximize income.
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118.26 USD hope this helped
Mark me Brainly answer 2/5
Equation in point slope form is given by y - y1 = m(x - x1); where m = (y2 - y1)/(x2 - x1).
y - 0 = (6 - 0)/(2 - 4) (x - 4)
y = 6/-2 (x - 4)
y = -3(x - 4)
Answer:
127.17 cm²
Step-by-step explanation:
- Area of a semicircle: 1/2*π*r²
- π (pi) = 3.14
- r (radius) = d (diamater) / 2 => 18/2 = 9 cm
A = 1/2*π*r²
A = 1/2*3.14*9²
A = 1/2*3.14*81
A = 3.14*40.5
A = 127.17 cm²
Therefore, the area of the semicircle is 127.17 cm²
Hope this helps!
Answer:3^2=9
U are gonna times 3 two times
Example:3x3=9
