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miss Akunina [59]
3 years ago
7

The area of a parking lot is 805 square meters. A car requires 5 meters and a bus requires 32 square meters of space. There can

be at most 80 vehicles parked at one time. If the cost to park a car is $2.00 and a bus is $6.00, how many should be in the lot to maximize income?
Mathematics
1 answer:
zlopas [31]3 years ago
6 0

Answer:

  80 cars will maximize revenue

Step-by-step explanation:

The revenue per square meter for parked cars is ...

  $2.00/5 = $0.40

The revenue per square meter for buses is ...

  $6.00/32 = $0.1875

Thus the available space should be used to park the maximum number of cars.

80 cars should be in the lot to maximize income.

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f(6) =   - 2

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5 0
3 years ago
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Helen [10]

Answer:

We have sinθ = 12/13

The  method here is to figure out the value of θ

Using a calculator sin^(-1)(12/13) =67.38°

67.38° is in quadrant 1  so we must substract 67.38° from 180° wich is π

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Now time to calculate cos2θ and cosθ using a calculator

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5 0
3 years ago
I need help with number 19
inysia [295]
Let's start by understanding that the graph is a linear line. We have a common difference if 4.5 for every 10x we have more.

We can start by finding the gradient, using rise over run. Let's take (10, 4.5) and (20, 9)

Our rise is 9 - 4.5 = 4.5 and our run is 10. Then, our gradient becomes 4.5/10 = 0.45

Now, we can substitute points using the point-slope form.

y - 4.5 = 0.45(x - 10)
y - 4.5 = 0.45x - 4.5
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4 0
3 years ago
6 × (9 + 9)
Aleksandr [31]

Answer:

C

Step-by-step explanation:

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4 0
3 years ago
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astra-53 [7]

Answer:

A.

Step-by-step explanation:

Given: limit of f(x) exists at x = a

To choose: the correct option

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A limit is a value that a function approaches as the input approaches some value.

\lim_{x\rightarrow a}f(x)=L means that as x approaches to value a then f(x) approaches to value L.

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3 years ago
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