Question

How many milliliters of a 0.266 M RbNO3 solution are required to make 150.0 mL of 0.075 M RbNO3 solution? How many milliliters of a 0.266 M RbNO3 solution are required to make 150.0 mL of 0.075 M RbNO3 solution? 42.3 mL 53.2 mL 35.1 mL 18.8 mL 23.6 mL

Answer 1

Answer : 42.3 ml of a 0.266 M $RbNO_3$ solution are required.

Solution : Given,

Molarity of $RbNO_3$ solution 1 = 0.266 M

Molarity of $RbNO_3$ solution 2 = 0.075 M

Volume of $RbNO_3$ solution 2 = 150 ml = 0.150 L      (1 L = 1000 ml)

Formula used :

$M_1V_1=M_2V_2$

where,

$M_1$ = Molarity of $RbNO_3$ solution 1

$M_2$ = Molarity of $RbNO_3$ solution 2

$V_1$ = Volume of $RbNO_3$ solution 1  

$V_2$ = Volume of $RbNO_3$ solution 2

Now put all the given values in above formula, we get

$0.266M\times V_1=0.075M\times 0.150L\\V_1=0.042293L=42.293ml\approx 42.3 ml$                 (1 L = 1000 ml)

Therefore, 42.3 ml of a 0.266 M $RbNO_3$ solution are required.