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2 years ago

How far will a rocket travel in 5s if it is moving 80m/s?

Chemistry

2 answers:

Dima020 [189]2 years ago

5 0

$speed = \frac{distance}{time}$

$distance = speed \times time$

$distance = 80 \times 5 = 400m$

Aleks [24]2 years ago

3 0

Time=5s
Speed=80m/s

$\\ \sf\longmapsto Distance=Speed(Time)$

$\\ \sf\longmapsto Distance=5(80)$

$\\ \sf\longmapsto Distance=400m$

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Answer : The partial pressure of $O_2$ is, 222.93 torr

Explanation :

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First we have to calculate the rate constant, we use the formula :

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$k=\frac{0.693}{168.6min}$

$k=4.11\times 10^{-3}min^{-1}$

Now we have to calculate the partial pressure of $O_2$

The balanced chemical reaction is:

$2N_2O_5(g)\rightarrow 4NO_2(g)+O_2(g)$

Initial pressure 760 0 0

At eqm. (760-2x) 4x x

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{P_o}{P_t}$

where,

k = rate constant

t = time passed by the sample = 215 min

a = initial pressure of $N_2O_5$ = 760 torr

a - x = pressure of $N_2O_5$ at equilibrium = (760-2x) torr

Now put all the given values in above equation, we get:

$215=\frac{2.303}{4.11\times 10^{-3}}\log\frac{760}{760-2x}$

$x=222.93torr$

The partial pressure of $O_2$ = x = 222.93 torr

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hodyreva [135]

Answer:

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Explanation:

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Regarding the other options:

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