Your answers would be, (Ex. 3*3*3*3....etc..).
(1), When measurements involving counting
(2), When measurement involves exactly defined quantities
Hope that helps!!!
Answer:
Carbon atoms in graphite and diamond are arranged in different ways. Hence, the two allotropes of carbon have different physical properties.
Explanation:
Both graphite and diamond are both made of only carbon atoms. However, their physical properties differ from each other. Hence, they are called allotropes. Think about how these carbon atoms are arranged in each of the allotropes.
<h3>Graphite</h3>
In graphite, each carbon atom is bonded to three other carbon atoms. These carbon atoms will be located in the same plane. A chunk of graphite can contain many of these planes.
Each carbon atom has four valence electrons. Three of these electrons will be used in the bonds. The other electron will be delocalized. These electrons would flow between the sheets of carbon atoms. That keeps the sheets separate and allow them to slide on top of each other.
<h3>Diamond</h3>
In diamond, each carbon atom is bonded to four other carbon atoms. These carbon atoms will form a tetrahedral network.
In graphite, there's a significant separation between two adjacent sheets of carbon atoms. The force between the two sheets is rather weak. When a piece of graphite is between two objects that move over one another, the layers in the graphite would also slide over one another. Since the attraction between two adjacent sheets isn't very strong, there wouldn't be much resistance. Hence the graphite acts as a lubricant.
In contrast, most of the carbon atoms in a piece of diamond would be connected to each other. Unlike the sheets in graphite, in a diamond there are almost no moving parts. Also, the forces between neighboring carbon atoms are very strong. When an external force acts on a chunk of diamond, the carbon atoms would barely move. Hence, the structure appears to be very rigid. That gives diamond its abrasive properties.
Answer:
Boiling- 212° F melting- 32°F
Explanation:
Answer:
207.03°C
Explanation:
The following data were obtained from the question:
V1 (initial volume) = 6.80 L
T1 (initial temperature) = 52.0°C = 52 + 273 = 325K
P1 (initial pressure) = 1.05 atm
V2 (final volume) = 7.87 L
P2 (final pressure) = 1.34 atm
T2(final temperature) =?
Using the general gas equation P1V1/T1 = P2V2/T2, the final temperature of the gas sample can be obtained as follow:
P1V1/T1 = P2V2/T2
1.05 x 6.8/325 = 1.34 x 7.87/T2
Cross multiply to express in linear form as shown below:
1.05 x 6.8 x T2 = 325 x 1.34 x 7.87
Divide both side by 1.05 x 6.8
T2 = (325 x 1.34 x 7.87) /(1.05 x 6.8)
T2 = 480.03K
Now, let us convert 480.03K to a number in celsius scale. This is illustrated below:
°C = K - 273
°C = 480.03 - 273
°C = 207.03°C
Therefore, the final temperature of the gas will be 207.03°C
