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2 years ago

What agent of weathering is acid precipitation?

Chemistry

1 answer:

Alona [7]2 years ago

3 0

It would be considered acid rain in the sense of dew fall

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5. At 20°C, the water autoionization constant, Kw, is 6.8 ´ 10–15. What is the H3O+ concentration in neutral water at this tempe

rjkz [21]

Explanation:

Let us assume that the concentration of [ $OH^{-}$ and $H^{+}$ is equal to x. Then expression for $K_{w}$ for the given reaction is as follows.

$K_{w} = [OH^{-}][H^{+}]$

$K_{w} = x^{2}$

$6.8 \times 10^{-15} = x^{2}$

Now, we will take square root on both the sides as follows.

$\sqrt{6.8 \times 10^{-15}} = \sqrt{x^{2}}$

$[H^{+}] = 8.2 \times 10^{-8}$ M

Thus, we can conclude that the $H_{3}O^{+}$ concentration in neutral water at this temperature is $8.2 \times 10^{-8}$ M.

8 0

2 years ago

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Which statement is true for the given reaction? Na2SO4(aq) + Mg(s) →

Arlecino [84]

Answer is: no reaction occurs.
No reaction occurs because magnesium (Mg) is less reactive than sodium (Na). Sodium is higher in activity series of metals and can not be reduced. Metal X will replace another metal Y in a solution if X is higher in the activity series.

4 0

2 years ago

Read 2 more answers

What is the Big Bang

Mnenie [13.5K]

the rapid expansion of matter from a state of extremely high density and temperature that according to current cosmological theories marked the origin of the universe.

7 0

2 years ago

Given the following at 25C calculate delta Hf for HCN (g) at 25C. 2NH3 (g) +3O2 (g) + 2CH4 (g) ---> 2HCN (g) + 6H2O (g) delta

AysviL [449]

Answer: The $\Delta H_f$ for HCN (g) in the reaction is 135.1 kJ/mol.

Explanation:

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. The equation used to calculate enthalpy change is of a reaction is:

$\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]$

For the given chemical reaction:

$2NH_3(g)+3O_2(g)+2CH_4(g)\rightarrow 2HCN(g)+6H_2O(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(2\times \Delta H_f_{(HCN)})+(6\times \Delta H_f_{(H_2O)})]-[(2\times \Delta H_f_{(NH_3)})+(3\times \Delta H_f_{(O_2)})+(2\times \Delta H_f_{(CH_4)})]$

We are given:

$\Delta H_f_{(H_2O)}=-241.8kJ/mol\\\Delta H_f_{(NH_3)}=-80.3kJ/mol\\\Delta H_f_{(CH_4)}=-74.6kJ/mol\\\Delta H_f_{(O_2)}=0kJ/mol\\\Delta H_{rxn}=-870.8kJ$

Putting values in above equation, we get:

$-870.8=[(2\times \Delta H_f_{(HCN)})+(6\times (-241.8))]-[(2\times (-80.3))+(3\times (0))+(2\times (-74.6))]\\\\\Delta H_f_{(HCN)}=135.1kJ$

Hence, the $\Delta H_f$ for HCN (g) in the reaction is 135.1 kJ/mol.

8 0

3 years ago

Which compares the problem associated with radioactive waste created from generating electricity using fusion reactions to waste

uysha [10]

Answer:

hello good person

Explanation:

8 0

2 years ago