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bazaltina [42]
3 years ago
7

What agent of weathering is acid precipitation?

Chemistry
1 answer:
Alona [7]3 years ago
3 0
It would be considered acid rain in the sense of dew fall
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When dissolved in water, a neutral molecule of calcium chloride dissociates into three ions - one calcium ion and two chloride i
Mashcka [7]

Explanation:

Calcium chloride is an ionic compound as it is formed by transfer of an electron to each chlorine atom.

So, being an ionic compound calcium chloride is able to dissociate completely into water.

Hence, the dissociation reaction will be as follows.

         CaCl_{2}(s) \rightarrow Ca^{2+}(aq) + 2Cl^{-}(aq)

Since, two electrons has been lost by single calcium atom. Therefore, calcium atom will have a charge of +2.

Thus, we can conclude that the charge on the calcium ion, in elementary units is +2.

8 0
3 years ago
What are 2 mixtures and explain your answer
liq [111]
Water and orange juice
Or orange juice and sodium chloride
3 0
3 years ago
Most atoms have no net charge because they have
Ne4ueva [31]

Atoms have no electric charge because the protons and electrons "cancel out" each others charges. Neutrons have no charge. What is the atomic number of an element? The atomic number is the number of protons in the atom's nucleus.

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6 0
3 years ago
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Practice Problem: True Stress and Strain A cylindrical specimen of a metal alloy 49.7 mm long and 9.72 mm in diameter is stresse
amm1812

Answer:

The true stress required = 379 MPa

Explanation:

True Stress is the ratio of the internal resistive force to the instantaneous cross-sectional area of the specimen. True Strain is the natural log to the extended length after which load applied to the original length. The cold working stress – strain curve relation is as follows,

σ(t) = K (ε(t))ⁿ, σ(t) is the true stress, ε(t) is the true strain, K is the strength coefficient and n is the strain hardening exponent

True strain is given  by

Epsilon t =㏑ (l/l₀)

Substitute㏑(l/l₀) for ε(t)

σ(t) = K(㏑(l/l₀))ⁿ

Given values l₀ = 49.7mm, l =51.7mm , n =0.2 , σ(t) =379Mpa

379 x 10⁶ = K (㏑(51.7/49.7))^0.2

K = 379 x 10⁶/(㏑(51.7/49.7))^0.2

K = 723.48 MPa

Knowing the constant value would be same as the same material is being used in the second test, we can find out the true stress using the above formula replacing the value of the constant.

σ(t) = K(㏑(l/l₀))ⁿ

l₀ = 49.7mm, l = 51.7mm, n = 0.2, K = 723.48Mpa

σ(t) = 723.48 x 106 x (㏑(51.7/49.7))^0.2

σ(t) = 379 MPa

The true stress necessary to plastically elongate the specimen is 379 MPa.

6 0
3 years ago
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Answer:

If you speak Any English i Think I will be able to help you Los Amigo

Explanation:

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