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Westkost [7]
3 years ago
5

Convert the given amount to the given unit. 24 yd; ft

Mathematics
1 answer:
kotegsom [21]3 years ago
6 0

Answer:

72 ft

Step-by-step explanation:

<em>1 yd = 3 ft</em>

24(3) = 72 yd

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Factor y + 5y + 6.<br> ??
maxonik [38]

Answer:

6(y+1)  Hope this helps!!

Step-by-step explanation:

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2 years ago
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7-x=-2<br><br> find the variable
nevsk [136]

Answer:

Step-by-step explanation:

7-x=-2

-x=-2-7

-x=-9

x=9

7 0
2 years ago
In 1950 the number of retirees was approximately 150 per thousand people aged 20-64. In 1990 this number rose to approximately 2
serg [7]

Answer: 233 people per thousand

Step-by-step explanation:

Using extrapolation method,

if 150/k in 1950,

  200/k in 1990,

  275/k in 2020,

2003 lies in between 1990 and 2020. So, you extrapolate the values of 200/k and 275/k for the years respectively.

Therefore,  

(2003 - 1990)/(2020 - 2003) = (x - 200)/(275 - x)

Where x is the number of retirees per thousand for 2003

Making x the subject of relation in the above equation.

Cross multiply the equation above;

(2003 - 1990)(275-x) = (2020 - 2003)(x - 200)

13(275 - x) = 17(x-200)

3575 - 13x = 17x - 3400

Collect the like terms

3575+3400 = 17x + 13x

30x = 6975

x = 6975/30

x = 232.5

x = 233 people per thousand to the nearest integer

6 0
3 years ago
Line P R and Line Q S are diameters of circle T. What is the measure of Arc S R?
a_sh-v [17]
100 is the correct answer to your question
4 0
3 years ago
At what values of x does f(x) = x^3 - 2x^2 -4x+1 satisfy the mean value theorwm on [0,1]
denis-greek [22]

Answer:

x=1/3

Step-by-step explanation:

A function f is given as

f(x) = x^3-2x^2-4x+1 in the interval  [0,1]

This function f being an algebraic polynomial is continuous in the interval [0,1] and also f is differntiable in the open interval (0,1)

Hence mean value theorem applies for f in the given interval

f(1) = 1-2-4+1 = -4\\f(0) = 1

The value

\frac{f(1)-f(0)}{1-0} =\frac{-4-1}{1} =-5

Find derivative for f

f'(x) = 3x^2-4x-4

Equate this to -5 to check mean value theorem

3x^2-4x-4=-5\\3x^2-4x+1=0\\\\(x-1)(3x-1) =0\\x= 1/3 : x = 1

We find that 1/3 lies inside the interval (0,1)

4 0
3 years ago
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