Convert the given amount to the given unit. 24 yd; ft

Please help it would be much appreciated!

sergiy2304 [10]

Answer:

Part a) Option d

Part b) Option a

Step-by-step explanation:

Part a

if we look at the options given and the data available

Option a) x^4+9

Putting x= 2 we get (2^4) + 9 =25

Putting x= 3 we get (3^4) + 9 =90 but f(x) =125 so not correct option

Option b) (4^x)+9

Putting x= 2 we get (4^2) + 9 =25

Putting x= 3 we get (4^3) + 9 =73 but f(x) =125 so not correct option

Option c) x^5

Putting x= 2 we get (2^5) =32 but f(x) =25 so not correct option

Option d) 5^x

Putting x= 2 we get (5^2) =25

Putting x= 3 we get (5^3) =125

Putting x= 4 we get (5^4) =625

So Option d is correct.

Part (b)

3(2)^3x

can be solved as:

=3(2^3)^x

=3(8)^x

So, correct option is a

8 0

3 years ago

Pls help me I have 5 min to do this!!!! PLS PLS PLS PLS PLS NO LINKS!!!! I can’t open them just pls give me the answer idc how y

nadezda [96]

Answer:

P(-8,6), Q(-5,2), R(2,1)

8 0

2 years ago

The sum of the areas of two circles is 80 pi

katovenus [111]

The area of a circle is A = πr^2. We let A1 And A2 the areas of the circles and r1 and r2 the radius of each, respectivley.

A1 + A2 = 80π
Substitute the formula for the area,
π(r1)^2 + π (r2)^2 = 80π

From the statement, we know that r2=2(r1).

π(r1)^2 + π (2 x r1)^2 = 80π
We can cancel π, we will have

5 x (r1)^2 = 80
Thus,

r1 = 4 and r2 = 8

5 0

3 years ago

Bobby knows that the perimeter of the original rectangle is 120 meters. He also knows that the perimeter of the reduced rectangl

Whitepunk [10]

Answer:

24 meters is the width of the original rectangle.

Step-by-step explanation:

Given:

Bobby knows that the perimeter of the original rectangle is 120 meters. He also knows that the perimeter of the reduced rectangle is 30 meters and the reduced rectangle has a length of 9 meters.

Now, to get the width of original rectangle.

The reduced rectangle's perimeter = 30 meters.

The reduced rectangle's length = 9 meters.

Now, we find the width of reduced rectangle by using formula:

Let the width of reduced rectangle be $x.$

$Perimeter=2\times length+2\times width$

$30=2\times 9+2\times x$

$30=18+2x$

Subtracting both sides by 18 we get:

$12=2x$

Dividing both sides by 2 we get:

$6=x\\\\x=6\ meters.$

The width of reduced rectangle = 6 meters.

Now, to get the width of original rectangle:

Let the width of original rectangle be $w.$

As given, the perimeter of the original rectangle = 120 meters.

And, the perimeter of reduced rectangle is 30 meters and its width is 6 meters.

So, 30 is equivalent to 6.

Thus, 120 is equivalent to $w.$

Now, to get the width using cross multiplication method:

$\frac{30}{6}=\frac{120}{w}$

By cross multiplying we get:

$30w=720$

Dividing both sides by 30 we get:

$w=24\ meters.$

The width of original rectangle = 24 meters.

Therefore, 24 meters is the width of the original rectangle.

6 0

2 years ago

Read 2 more answers

2. Solve the following system of equations using substitution.

SOVA2 [1]

First, make sure you convert both equations into standard form. Your two equations would be 2x+2y=38 and -x+y=3. Then multiply the bottom by 2. So your new equations would be 2x+2y=38 and -2x+2y=6. The x would cancel out and you would continue solving for y. y would equal 11 and then you would plug it back into an original equation. When you plug and solve for x, you would get x=8. So your answer would be (8,11)

4 0

3 years ago