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guajiro [1.7K]
3 years ago
15

What is the mass of an object with a net force of 10 N accelerating at 2 m/s^2??

Chemistry
1 answer:
xz_007 [3.2K]3 years ago
5 0

Answer:

5kg

Explanation:

Force = Mass x acceleration

F = ma

m = F/a = 10N/2m/s^2

m = 10/2 = 5kg

The standard unit for mass = Kilogram

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Which is the smallest number?
My name is Ann [436]

Answer:

What I came up with was D equaling out to be 42

Explanation:

Im assuming you just do the math

A. 3.5 x 104 = 364

B. 2.4 x 103 = 247.2

C. 1.4 x 10^2_2 = 280

D. 4.9 x 10-7 = 42

I hope I helped.

5 0
3 years ago
How many O atoms are in 4C₆H₁₂O₆
ipn [44]

Number of O atoms : 24

<h3>Further explanation</h3>

Given

C₆H₁₂O₆ compound

Required

Number of atoms

Solution

A molecular formula  shows the number of atomic elements in compound.  

The empirical formula is the smallest comparison of the atoms

Glucose-C₆H₁₂O₆ is composed of 3 elements, namely C, H, and O.

The number of atoms in a compound can usually be seen from the subscript number after the atom and the reaction coefficient shows the number of molecules

So number of O atoms :

= 4 x 6 = 24 atoms

6 0
3 years ago
What is the decay mode of radium-226?
inn [45]

Answer:

Radium-226 is a radioactive decay product in the uranium-238 decay series and is the precursor of radon-222. Radium-228 is a radioactive decay product in the thorium-232 decay series. Both isotopes give rise to many additional short-lived radionuclides, resulting in a wide spectrum of alpha, beta and gamma radiations.

6 0
3 years ago
The table shows the volumes of different samples of liquid? Which sample has the greatest DENSITY.
arlik [135]

Answer:

Maybe B

Explanation:

4 0
3 years ago
Read 2 more answers
An 80.0-gram sample of water at 10.0°C absorbs 1680 Joules of heat energy. What is the final temperature of the water? a 50.0°C
ICE Princess25 [194]

Answer:

b)15.0°C

Explanation:

Specific Heat of Water=4.2 J/g°C

This means, that 1 g of Water will take 4.2 J of energy to increase its temperature by 1°C.

∴80 g Water will take 80×4.2 J of energy to increase its temperature by 1°C.

80×4.2 J=336 J

Total Energy Provided=1680 J

The temperature increase=\frac{\textrm{Total energy required}}{\textrm{energy required to increase temperature by one degree}}

Temperature increase=\frac{1680}{336}

=5°C

Initial Temperature =10°C

Final Temperature=Initial + Increase in Temperature

=10+5=15°C

7 0
3 years ago
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