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4 years ago

What characteristics identify a substance?

Chemistry

1 answer:

Nataliya [291]4 years ago

4 0

Answer:

All substances can be characterized by their unique sets of physical and chemical properties.

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The half-life of tritium (H-3) is 12.3 years. If 48.0mg of tritium is released from a nuclear power plant during the course of a

Rudiy27

Answer:

The amount left after 49.2 years is 3mg.

Explanation:

Given data:

Half life of tritium = 12.3 years

Total mass pf tritium = 48.0 mg

Mass remain after 49.2 years = ?

Solution:

First of all we will calculate the number of half lives.

Number of half lives = T elapsed/ half life

Number of half lives = 49.2 years /12.3 years

Number of half lives = 4

Now we will calculate the amount left after 49.2 years.

At time zero 48.0 mg

At first half life = 48.0mg/2 = 24 mg

At second half life = 24mg/2 = 12 mg

At 3rd half life = 12 mg/2 = 6 mg

At 4th half life = 6mg/2 = 3mg

The amount left after 49.2 years is 3mg.

6 0

4 years ago

The human body has several major systems. Most body systems have multiple functions. Which of the following is NOT a major funct

tensa zangetsu [6.8K]

Answer:D

Explanation:

i got it right LOL

8 0

3 years ago

Which is an example of chemical change

Oksanka [162]

Mixing of posted colours

4 0

3 years ago

Fundamental differences in the cell, the basic unit of life, allow for broadest classification of all living organisms into thre

Nana76 [90]

Answer:

Explanation:

7 0

3 years ago

You have two containers at 25°C and 1 atm. One has 22.4 L of hydrogen gas, and the other has 22.4 L of oxygen gas.

olga_2 [115]

Both containers have the same number of molecules= 5.62 x 10²³

<h3>Further explanation</h3>

Given

22.4 L of hydrogen gas

22.4 L of oxygen gas

25°C and 1 atm.

Required

true statement

Solution

Conditions at T 25 ° C and P 1 atm are stated by RTP (Room Temperature and Pressure). Vm in this condition = 24 liters / mol

and from Avogadro's Law :

<em>At the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles </em>

So two gas have the same molecules

1 mol = 6.02 x 10²³ molecules

24 L = 1 mol, so for 22.4 L :

$\tt \dfrac{22.4~L}{24~L}\times 6.02\times 10^{23}~molecules=5.62\times 10^{23}~molecules$

6 0

3 years ago