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Kay [80]
3 years ago
10

What is the weight, on earth, if a book with a mass of 1.5kg 1.5N 6.5 N 11.3 N 14.7

Chemistry
2 answers:
Artemon [7]3 years ago
7 0

Consider the equation for weight:

W=mg

W is the weight, m is the mass, and g is the acceleration due to gravity.

Therefore, to calculate the weight of an object, just multiply its mass by the acc. due to gravity of the location.

The acc. due to gravity on Earth is approximately 9.81 ms^-2, note that this number may change from place to place, for example, the acc. due to gravity on moon is only 1/6 of Earth's. (Sometimes the question provides g as 10, so make sure you check the instructions before!)

W = 1.5 x 9.81

   = 14.715N (≈14.7N)

Therefore, the answer to this question is the last option (or D), 14.7N.

Delvig [45]3 years ago
4 0

Answer:

the answer is D.  14.7

Explanation:

just took the test

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melisa1 [442]

Answer : The correct option is, -NH_2

Explanation :

Amino acid : The acid that contains two functional groups that are carboxylic group, -COOH and ammine group, -NH_2.

When the two or more that two amino acids join together with the help of peptide bond, they produces polypeptide chain or protein.

The bond present between the two amino acid is called a peptide bond.

The peptide bond is a chemical bond that is formed between the two molecules when the nitrogen of one amino acid react with the carbon of another amino acid by releasing a water molecule. This is a dehydration synthesis or condensation reaction.

From this we conclude that, only two functional groups carboxylic group, -COOH and ammine group, -NH_2 are present in all amino acids.

Hence, the correct option is, -NH_2

7 0
3 years ago
a cylinder rod formed from silicon is 46.0 cm long and has a mass of 3.00 kg. the density of silicon is 2.33 g/cm³. what is the
Gnesinka [82]
d=\frac{m}{V}\\\\
V=\pi r^{2}H\\d=\frac{m}{\pi r^{2}H} \ \ \ |*\pi r^{2}H\\\\
d \pi r^{2}H=m \ \ \ |:d \pi H\\\\
r^{2}=\frac{m}{d \pi H}\\\\
r=\sqrt{\frac{m}{d \pi H}}\\\\
2r=d\\\\
d=2\sqrt{\frac{m}{d \pi H}}

H=43cm\\
d=2.33\frac{g}{cm^{3}}\\
m=3kg=3000g\\\\
d=2\sqrt{\frac{m}{d \pi H}}=2*\sqrt{\frac{3000g}{2.33\frac{g}{cm^{3}} * \pi * 43cm}}=2*\sqrt{\frac{3000}{100,19\pi \frac{1}{cm^{2}}}}\approx6,17cm
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Answer:

--- The hot air inside the bottle creates an expansion and when the hot water is applied a contraction occurs, thus causing the balloon to be sucked.

--- An internal pressure is produced, joining the heat begins to decrease. As a consequence, the air molecule causes the balloon to enter the bottle thanks to the effect of the external pressure.

Explanation:

I hope I have helped with something.

4 0
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Answer:

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