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Kay [80]
3 years ago
10

What is the weight, on earth, if a book with a mass of 1.5kg 1.5N 6.5 N 11.3 N 14.7

Chemistry
2 answers:
Artemon [7]3 years ago
7 0

Consider the equation for weight:

W=mg

W is the weight, m is the mass, and g is the acceleration due to gravity.

Therefore, to calculate the weight of an object, just multiply its mass by the acc. due to gravity of the location.

The acc. due to gravity on Earth is approximately 9.81 ms^-2, note that this number may change from place to place, for example, the acc. due to gravity on moon is only 1/6 of Earth's. (Sometimes the question provides g as 10, so make sure you check the instructions before!)

W = 1.5 x 9.81

   = 14.715N (≈14.7N)

Therefore, the answer to this question is the last option (or D), 14.7N.

Delvig [45]3 years ago
4 0

Answer:

the answer is D.  14.7

Explanation:

just took the test

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Which ion has the smallest radius?<br> (1) O2-<br> (2) S2-<br> (3) Se2-<br> (4) Te2-
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Answer:


                  Option-1 (O²⁻) is the correct answer.


Explanation:

                       All given anions contains same charge. So, we can ignore the effect of charge on these anions.


As we know all given compounds belongs to same group (Group 6) in periodic table. And from top to bottom along the group the elements are placed as,


                                                          Oxygen O


                                                          Sulfur S


                                                          Selenium Se


                                                          Tellurium Te


Hence, moving from top to bottom along the group the number of shells increases. And with increase in number of shell the atomic or ionic radii increases. As Oxygen is present at the top of the group, therefore, it has the smallest radius due to less number of shells.

5 0
3 years ago
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7 0
2 years ago
Calculate the number of Li atoms in 7.8 mol of Li.
Gwar [14]
<h3>Answer:</h3>

4.7 × 10²⁴ atoms Li

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

7.8 mol Li

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 7.8 \ mol \ Li(\frac{6.022 \cdot 10^{23} \ atoms \ Li}{1 \ mol \ Li})
  2. Multiply/Divide:                \displaystyle 4.69716 \cdot 10^{24} \ atoms \ Li

<u>Step 4: Check</u>

<em>We are told to round to 2 sig figs. Follow sig fig rules and round.</em>

4.69716 × 10²⁴ atoms Li ≈ 4.7 × 10²⁴ atoms Li

6 0
2 years ago
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