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Jobisdone [24]
2 years ago
12

If two objects repel from one another, what must be happening on the subatomic scale?

Chemistry
1 answer:
Kipish [7]2 years ago
7 0

Answer:

The electromagnetic force is at work. They must have the same charge. for example, two electrons repel each other.

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Food in the stomach is broken down by powerful acids and turned into?
zheka24 [161]
<span>In this particular item, we are to determine how we call the acidic fluid-like substance that is formed after the food in the stomach is broken down by a powerful acid. The answer to this question is CHYME. The powerful acid that is referred in this item is more specifically gastric juices. </span>
4 0
4 years ago
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Find density of nitrogen dioxide at 75*C and 0.805 atm.
Eva8 [605]

Answer:

1 (348) (D2) = 273 (2.05) (0.805) D2= 1.29 g/L

Explanation:

5 0
4 years ago
You work for a cutlery manufacturer who wants to electrolytically precipitate 0.500 g of silver onto each piece of a batch of 25
ICE Princess25 [194]

Answer:

373.1 mL of AgCN (aq) must be poured into your electrolysis vat to ensure you have sufficient Ag to plate all of the forks.

Explanation:

Mass of silver to be precipitated on ecah spoon = 0.500 g

Number of silver spoons = 250

Total mass of silver = 250 × 0.500 g = 125 g

Moles (n)=Molarity(M)\times Volume (L)

Moles of AgCN = n  = \frac{125 g}{134 g/mol}=0.9328 mol

Volume of AgCN solution =V

Molarity of the AgCN = 2.50 M

V=\frac{0.9328 mol}{2.50 M}=0.3731 L=373.1 mL

(1 L = 1000 mL)

373.1 mL of AgCN (aq) must be poured into your electrolysis vat to ensure you have sufficient Ag to plate all of the forks.

6 0
4 years ago
Calculate the volume of a 0.225M solution of KOH required to react with 0.215g of acetic acid.
Sidana [21]
Hope this might help ask me if u have any doubts

7 0
3 years ago
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How many dm3 of oxygen at STP would be required to react completely with 38.8g of propane? (3 marks)
11Alexandr11 [23.1K]

98.56 dm^3 of oxygen at STP would be required to react completely with 38.8g of propane.

<u>Given that :</u>

molar mass of propane = 44 g/mol

mass of propane = 38.8 g

∴ Moles present in 38.8 g of propane = \frac{38.8}{44} = 0.88 mole

<u>applying rule of balanced equations </u>

1 mole of propane = 5 moles of oxygen

0.88 mole of propane =  5 * 0.88 = 4.4 moles of oxygen

Note : volume of 1 mole of oxygen at STP = 22.4 dm^3

∴Total volume of oxygen required at STP = 22.4 * 4.4 = 98.56 dm^3

Hence we can conclude that the volume of oxygen at STP required to react completely 98.56 dm^3

Learn more : brainly.com/question/16998374

5 0
2 years ago
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