Hydrogen gas, oxygen gas and water
4H2O (l) ---> 2H2O (l) + O2 (g) + 2H2 (g)
Answer:
The answer to your questions is: C. Sulfides
Explanation:
A. Phosphates these compounds do not have sulphur, they are composed by phosphate and oxygen, So this answer is wrong.
B. Sulfates are formed by sulphur and oxygen, not for a metal, then this is not the right answer.
C. Sulfides are molecules formed by a metal and sulphur, this is the anwser to the question.
D. Silicates are formed by sillicon and oxygen, this option is incorrect.
The keg for the reaction
2 SO2(g) + O2(g) → 2 SO3(g) is
Keg = [SO3]^2/ {(SO2)^2 ( O2)}
Keg (equilibrium constant) is the ratio of of equilibrium concentration of the product raised to the power of their stoichiometric coefficient to the equilibrium concentration of the reactant raised to the power of their stoichiometric coefficient.
Answer:
Second order
Explanation:
We could obtain the order of reaction by looking at the table very closely.
Now notice that in experiment 1 and 2, the concentration of [OH^-] was held constant while the concentration of [S8] was varied. So we have;
a situation in which the rate of reaction was tripled;
0.3/0.1 = 2.10/0.699
3^1 = 3^1
Therefore the order of reaction with respect to [S8] is 1.
For [OH^-], we have to look at experiment 2 and 3 where the concentration of [S8] was held constant;
x/0.01 = 4.19/2.10
x/0.01 = 2
x = 2 * 0.01
x = 0.02
So we have;
0.02/0.01 = 2^1
2^1 = 2^1
The order of reaction with respect to [OH^-] = 1
So we have the overall rate law as;
Rate = k[S8]^1 [OH^-] ^1
Overall order of reaction = 1 + 1 = 2
Therefore the reaction is second order.
Protons, neutrons, and electrons.
