4(2x+1)=29+3(2x-5) Just trying to solve this for X.
1 answer:
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Step-by-step explanation:
Consider the provided information.
The total number of students are: 24+26+21=71
He wants each team will have the same number of students between 5 and 9.
The number between 5 to 9 are 6, 7 and 8.
The number 71 is a prime number so we need to divide the 71 students in group so that minimum students left without team.
Dividing 6 students in each group.
Number of teams: = 11 teams and 5 students.
Dividing 7 students in each group.
Number of teams: = 10 teams and 1 students.
Dividing 8 students in each group.
Number of teams: = 8 teams and 7 students.
Thus, we can not divide 71 students into equal teams, but 70 divided by 7 gives the least students left out i.e 10 teams each with 7 students and only 1 student will remain at last.