Question

In your Pre-Calc class 60% of the students have brown hair, 30% have brown eyes and 10% have both brown hair and brown eyes. A student is chosen randomly. Find each probability.

Answer 1

Probability of the students having brown hair =  0.6

Probability of the students having brown eyes = 0.3

Probability of the students having both brown hair and brown eyes = 0.1

Step-by-step explanation:

Step 1 :

Given,

Percentage of the students having brown hair = 60%

Percentage of the students having brown eyes = 30%

Percentage of the students having both brown hair and brown eyes = 10%

We need to obtain the probability of each separately, when a student is chosen randomly

Step 2 :

The probability of each event happening given its percentage, can be obtained by dividing the corresponding percentage by 100.

Hence we have,

Probability of the students who have brown hair =  $\frac{60}{100}$ = 0.6

Probability of the students who have brown eyes = $\frac{30}{100}$ = 0.3

Probability of the students who has both brown hair and  eyes = $\frac{10}{100}$ = 0.1

Step 3 :

Answer :

Probability of the students who have brown hair =  0.6

Probability of the students  who have brown eyes = 0.3

Probability of the students  who has both brown hair and  eyes = 0.1