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2 years ago

5

The total charge that an automobile battery can supply without being recharged is given in terms of Ampere-hours. A typical 12-V

battery has a rating of 49 A · h . Suppose you forget to turn off the headlights in your parked automobile. If each of the two headlights draws 3.5 A , find out the time before your battery is "dead". Answer in units of hours. Answer in units of h

1 answer:

anyanavicka [17]2 years ago

5 0

Answer:

7 hours

Explanation:

The total charge contained in the battery is

$Q = 49 A \cdot h$

And this is a charge, since it is a current multiplied by a time:

$Q=It$

The current drawn by each headlight (which is the charge consumed per second) is

$I=3.5 A$

Since we have two headlight, the total current drawn is

$I=3.5 \cdot 2 = 7 A$

Therefore, the total charge consumed by the two headlights each hour is

$q = I \cdot h = 7 A \cdot h$

So, the time before the battery is dead is

$t=\frac{Q}{q}=\frac{49 Ah}{7Ah}=7 h$

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Answer:

Explanation:

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Now when a match stick is lit in the path of a wave , the fringes will disappear and an general illumination will be observed on the screen as the light from the lit match stick will not be coherent . Incoherent light can not form stable fringes.

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2 years ago

A hard-boiled egg of mass 46.0 gg moves on the end of a spring with force constant 25.6 N/mN/m . The egg is released from rest a

soldi70 [24.7K]

Answer:

0.022kg/s

Explanation:

We are given that

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$1kg=1000 g$

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Initial displacement= $A_1=0.296 m$

Final displacement= $A_2=0.12 m$

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Damping force= $F_x=-bv_x$

We have to find the magnitude of damping constant b.

We know that the displacement of the oscillator under damping motion is given by

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For maximum displacement $cos(w't+\phi)=1$

Therefore , $x=A_2$

Substitute the values

$A_2=A_1e^{-\frac{-b}{2m}t}$

$e^{-\frac{b}{2m}t}=\frac{A_2}{A_1}$

$-\frac{b}{2m}t=ln\frac{A_2}{A_1}$

$lnx=y\implies x=e^y$

Substitute the values

$-\frac{b}{2\times 0.046}\times 4.55=ln\frac{0.12}{0.296}$

$\frac{2\times 0.046}{4.55b}=ln\frac{0.296}{0.12}$

$\frac{2\times 0.046}{4.55}=0.9b$

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Answer:

The speed will be "18km/s". A further explanation is given below.

Explanation:

According to the question, the values are:

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$c=3\times 10^8$

As we know,

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On substituting the values, we get

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or,

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KATRIN_1 [288]

Answer:

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Explanation:

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mihalych1998 [28]

Answer:

See the explanation below

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