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nikklg [1K]
3 years ago
5

The total charge that an automobile battery can supply without being recharged is given in terms of Ampere-hours. A typical 12-V

battery has a rating of 49 A · h . Suppose you forget to turn off the headlights in your parked automobile. If each of the two headlights draws 3.5 A , find out the time before your battery is "dead". Answer in units of hours. Answer in units of h
Physics
1 answer:
anyanavicka [17]3 years ago
5 0

Answer:

7 hours

Explanation:

The total charge contained in the battery is

Q = 49 A \cdot h

And this is a charge, since it is a current multiplied by a time:

Q=It

The current drawn by each headlight (which is the charge consumed per second) is

I=3.5 A

Since we have two headlight, the total current drawn is

I=3.5 \cdot 2 = 7 A

Therefore, the total charge consumed by the two headlights each hour is

q = I \cdot h = 7 A \cdot h

So, the time before the battery is dead is

t=\frac{Q}{q}=\frac{49 Ah}{7Ah}=7 h

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Answer:

88.89kg

Explanation:

The formula for mass is m=F/a. If we plug in the values, we get m=400N/4.5m/s^2. The mass is 88.89kg. We know that the unit is in kg because one newton (N) is 1kg*m/s^2. The m/s^2 is cancelled out by the acceleration, and we are left with kg.

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3 years ago
An object moving with a constant
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Answer:

Acceleration:

{ \tt{a =  \frac{v - u}{t} }} \\ { \tt{a =  \frac{20 - 10}{5} }} \\ { \tt{a = 2 \: m {s}^{ - 2} }}

From third equation:

{ \bf{ {v}^{2}  =  {u}^{2}  + 2as}} \\ { \tt{s =  \frac{ {20}^{2}  -  {10}^{2} }{2 \times 2} }} \\   = { \tt{s = 75 \: m}}

5 0
3 years ago
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The propeller of an airplane is at rest when the pilot starts the engine; and its angular acceleration is a constant value. Two
Maurinko [17]

Answer:0.318 revolutions

Explanation:

Given

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after t=10 s

\omega =10 rad/s

using \omega =\omega _0+\alpha t

10=0+\alpha \cdot 10

\alpha =1 rad/s^2

Revolutions turned in 2 s

\theta =\omega _0t+\frac{\alpha t^2}{2}

\theta =0+\frac{1\times 2^2}{2}

\theta =2 rad

To get revolution \frac{\theta }{2\pi }

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3 0
3 years ago
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Answer:

2.145×10^-10 V or 0.2145nV

Explanation:

From hf=eV

h= Plank's constant = 6.6×10^-34JS

f= frequency of the electromagnetic wave = 5.2×10^4 Hz

e= electronic charge= 1.6×10^-19 C

V= voltage

V= hf/e

V= 6.6×10^-34JS × 5.2×10^4 Hz/ 1.6×10^-19 C

V= 2.145×10^-10 V or 0.2145nV

Therefore the voltage created is 2.145×10^-10 V or 0.2145nV

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3 years ago
The ionosphere lies between the mesosphere and exosphere is it true or false
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False because the Ionsophere lies between the Mesosphere and the Theromsphere. If can can you give me brainliest :o ?

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