The total charge that an automobile battery can supply without being recharged is given in terms of Ampere-hours. A typical 12-V
1 answer:
Answer:
7 hours
Explanation:
The total charge contained in the battery is
And this is a charge, since it is a current multiplied by a time:
The current drawn by each headlight (which is the charge consumed per second) is
Since we have two headlight, the total current drawn is
Therefore, the total charge consumed by the two headlights each hour is
So, the time before the battery is dead is
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If the distance between two charges is halved, the electrical force between them increases by a factor 4.
In fact, the magnitude of the electric force between two charges is given by:
where
k is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the two charges
We see that the magnitude of the force F is inversely proportional to the square of the distance r. Therefore, if the radius is halved:
the magnitude of the force changes as follows:
so, the force increases by a factor 4.
In fact, the magnitude of the electric force between two charges is given by:
where
k is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the two charges
We see that the magnitude of the force F is inversely proportional to the square of the distance r. Therefore, if the radius is halved:
the magnitude of the force changes as follows:
so, the force increases by a factor 4.
Explanation:
Given that,
Size of object, h = 0.066 m
Object distance from the lens, u = 0.210 m (negative)
Focal length of the converging lens, f = 0.14 m
If v is the image distance from the lens, we can find it using lens formula as follows :
(a) Magnification,
(b) Magnification,
h' is image height
Hence, this is the required solution.