Which statements represent properties of intermolecular forces? Select all that apply.

The micrometer (1 μm) is often called the micron. (a) How many microns make up 3.0 km? (b) How many centimeters equal 3.0 μm? (c

Tomtit [17]

Answer:

3 x 10⁻⁹km

3 x 10⁻⁴cm

2.73 x 10⁶μm

Explanation:

A micron is a subunit of measurement usually for length dimensions.

1μm = 1 x 10⁻⁶m

a. How many microns make up 3km;

Now convert to meter first;

1000m = 1km

So, 3km will be made up of 3000m

So;

1 x 10⁻⁶m = 1μm

3000m = $\frac{3000}{1 x 10^{-6} }$ = $\frac{3 x 10^{3} }{ 1 x 10^{-6} }$ = 3 x 10⁻⁹km

b. How many centimeters equal 3.0 μm?

Since;

1μm = 1 x 10⁻⁶m

3μm = 3 x 1 x 10⁻⁶ = 3 x 10⁻⁶m

So;

100cm = 1m;

1m = 100cm

3 x 10⁻⁶m = 3 x 10⁻⁶ x 10² = 3 x 10⁻⁴cm

c. How many microns are in 3.0 yd?

1yd = 0.91m

3yd = 3 x 0.91 = 2.73m

So;

1 x 10⁻⁶m = 1μm

2.73m will give $\frac{2.73}{1 x 10^{-6} }$ = 2.73 x 10⁶μm

3 0

3 years ago

Elena puts her eggs in a cage made out of wood. The wood breaks during

artcher [175]

Answer:

I think the answer is Decreases the time that the egg slows down.

Explanation:

If not try it starts slowing down

O Increases the time that the egg slows down.

7 0

3 years ago

A proton and a deuteron are moving with equal velocities perpendicular to a uniform magnetic field. A deuteron has the same char

Leokris [45]

Answer:

option (b)

Explanation:

mass of proton, mp = m

mass of deuteron, md = 2m

charge on proton, qp = q

charge on deuteron, qd = q

The magnetic force on the charged particle when it is moving is given by

F = q v B Sinθ

where, θ is the angle between the velocity and magnetic field.

Here, θ = 90°

Let v is the velocity of both the particle when they enters in the magnetic field.

The force on proton is given by

Fp = q x v x B ...... (1)

The force on deuteron is

Fd = q x v x B .... (2)

Divide equation (1) by equation (2)

Fp / Fd = 1

Thus, the ratio of force on proton to the force on deuteron is 1 : 1.

Thus, option (b) is correct.

7 0

3 years ago

A dipole is located at the origin, with charges +3 nC and -3 nCseparated by 4 μm. Consider a spherical Gaussian surfacecentered

kirza4 [7]

Answer:

Explanation:

a )

The Gaussian surface must have contained both the charges like +3 nC and - 3 nC , total charges being zero . According the Gauss's law , total electric flux over a closed surface is equal to 1 / ε₀ times the total charge contained inside the closed surface .

Since total charge inside is zero , total flux will be 1 / ε₀ x 0 = 0

b )

In this case the Gaussian surface is so small that it contains only the charge

+ 3 nC .

So electric flux over the Gaussian surface

= ( 1 / ε₀ ) x 3 x 10⁻⁹

= (1 / 8.85 x 10⁻¹² ) x 3 x 10⁻⁹

= 3 x 10³ / 8.85

= 339 weber.

=

6 0

3 years ago

A block of mass 2. 0 kg, starting from rest, is pushed with a constant force across a horizontal track. The position of the bloc

yan [13]

The magnitude of the change in momentum of the block between zero and 4. 0 seconds is

dp=1.6m/s

<h3>What is the magnitude of the change in momentum of the block between zero and 4. 0 seconds?</h3>

Generally, the equation for the kinematics equation is mathematically given as

x=x+ut+0.5at^2

Therefore

1.6=0+0+0.5*a*1^2

a=0.2m/s^2

In conclusion, change in momentum

dP=mv-mu

2.0*0.8-0

dp=1.6m/s