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lbvjy [14]
3 years ago
14

a horizontal force of 300 N is needed to push a crate along the floor at constant speed. What is the friction force on the crate

?
Physics
1 answer:
finlep [7]3 years ago
5 0

Answer:

Since a 100-N force is being used to push the crate in one direction, and there is a total net force of 0, the force of friction acting on the crate must also be 100 N. This frictional force points in the direction opposite of the push.

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In an inelastic collision involving an isolated system, the final total momentum is
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Answer: B) exactly the same as the initial momentum.

Explanation:

An inelastic collision occurs when the elements that collide remain together after the collision, and althogh the kinetic energy is not conserved because is transformed into other kinds of energy (thermal energy, for example), the linear momentum does.  

This means the initial momentum before the collision will be equal to the final momentum after the collision:

p_{o}=p_{f}

8 0
3 years ago
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ASAP When salt is dissolved in water, the result is a A. gas B. compound C. homogeneous mixture D. heterogeneous mixture
alisha [4.7K]
It’s actually C. homogeneous compound because when they combine you can’t separate them
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3 years ago
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A student removes a 10.5 kg stereo amplifier from a shelf that is 1.82 m high. The amplifier is lowered at a constant speed to a
Nonamiya [84]

Answer:

(a) the work done by the student is 110.1 J

(b) The gravitational force that acts on the amplifier is 102.9 N

Explanation:

Given;

mass of the amplifier, m = 10.5 kg

initial position of the amplifier, x₀ = 1.82 m

final position of the amplifier, x₁ =0.75 m

The dispalcement of the amplifier Δx = x₁ - x₀ = 1.82 m - 0.75 m = 1.07 m

(b) The gravitational force that acts on the amplifier;

F = mg

F = 10.5 x 9.8

F = 102.9 N

(a) the work done by the student is calculated as;

W = FΔx

W = 102.9 x 1.07

W = 110.1 J

7 0
3 years ago
Find the work done in pumping gasoline that weighs 6600 newtons per cubic meter. A cylindrical gasoline tank 3 meters in diamete
almond37 [142]

Answer:

<em>work done in pumping the entire fuel is 1399761 J</em>

Explanation:

weight per volume of the gasoline = 6600 N/m^3

diameter of the tank = 3 m

length of the tank = 6 m

The height of the tractor tank above the top of the tank = 5 m

The total volume of the fuel is gotten below

we know that the tank is cylindrical.

<em>we assume that the fuel completely fills the tank.</em>

therefore, the volume of a cylinder =  

where r = radius = diameter ÷ 2 = 3/2 = 1.5 m

volume of the cylinder = 3.142 x  x 6 = 42.417 m^3

we then proceed to find the total weight of the fuel in Newton

total weight = (weight per volume) x volume

total weight = 6600 x 42.417 = 279952.2 N

therefore,

the work done to pump the fuel through to the 5 m height = (total weight of the fuel) x (height through which the fuel is pumped)

work done in pumping = 279952.2 x 5 = <em>1399761 J</em>

5 0
3 years ago
Two satellites orbit the Earth in circular orbits of the same radius. One satellite is twice as massive as the other. Which stat
loris [4]

To solve this problem it is necessary to apply the concepts related to the orbital velocity of a satellite on earth.

This concept is expressed in the equation,

v = \sqrt{\frac{Gm_E}{r}}

Where,

G = Universal Gravitational constant

m_E = Mass of the Earth

Therefore the ratio of the velocity from two satellites is,

\frac{v_1}{v_2} = \sqrt{\frac{r_2}{r_1}}

The ratio between the two satellites is the same, then

\frac{v_1}{v_2} = \sqrt{\frac{r}{r}}

\frac{v_1}{v_2} = 1

v_1 =v_2

Therefore the correct option is B.

4 0
3 years ago
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