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zhenek [66]
3 years ago
7

Suppose you are driving a car and your friend, who is with you in the car, tosses a softball up and down from her point of view.

A second friend of yours stands on the street and sees you passing by and says, "You are testing projectile motion with the softball!". Your friend on the street claims that each of you measures a different value for the vertical component of the initial velocity of the softball. Do you agree with the statement?
Physics
1 answer:
Sholpan [36]3 years ago
3 0

Answer:

No, i disagree.

Explanation:

If the car is moving, it only has a velocity with a component in the horizontal direction. If we use galilean relativity, the velocity of the ball observed by my friend standing in the ground should only be affected in the horizonal direction, while the vertical stays the same for both observers.

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Alex17521 [72]
W=MG
w is weight 
m is mass
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W=(100 kg)(9.8 m/s)
W= 980 N
hope this helps
7 0
3 years ago
What is the total amount of force needed to keep a 6.0 kg object moving at speed
DanielleElmas [232]

Answer:

C. 0 N

Explanation:

In the absence of external forces, a body in motion will stay in motion.

F = ma

F = 6.0(0) = 0

8 0
3 years ago
Read 2 more answers
A 1.50-m-long rope is stretched between two supports with a tension that makes the speed of transverse waves 48.0 m/s. What are
astra-53 [7]

Answer: a) 16Hz, 3m b) 48Hz, 1mc) 80Hz, 0.6m

Explanation:

a) Fundamental frequency in string is represented as Fo = V/2L where;

Fo is the fundamental frequency

V is the speed of the transverse wave = 48m/s

L is the length of the wire. = 1.50m

Substituting this values in the formula given we have;

Fo = 48/2(1.5)

Fo = 48/3

Fo = 16Hz

The fundamental tone is therefore 16Hz

Using v =f¶

Where f is the frequency and ¶ is the wavelength, the wavelength of the fundamental note will be;

¶ = v/fo

¶ = 48/16 = 3m

b) Overtones or harmonics is the multiple integral of the fundamental frequency. The multiples are I'm arithmetical progression.

First overtone f1 = 2fo

Second overtone f2 = 3fo etc.

Since fo = 16Hz

Second overtone f2 = 3×16 = 48Hz

¶ = v/f2 = 48/48

¶ = 1m

c) Fourth harmonic or overtone will be f4 = 5fo

F4 = 5×16 = 80Hz

The fourth harmonic is therefore 80Hz

¶ = v/f4 = 48/80

¶ = 0.6m

4 0
3 years ago
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blagie [28]

Answer:

hey

Explanation:

4 0
3 years ago
Use wave equation calculate the speed of sound in the air if frequency of 110 hz has a wave length of 3 m
kirill115 [55]
Answer = 330 m/s

The wave equation is as follows:

Wave speed = wavelength x frequency

The known values are:
Wavelength = 3m
Frequency = 110 Hz

Substitute the known values into the wave equation to find the wave speed.

Wave speed = 3 x 110

Wave speed = 330 m/s
8 0
2 years ago
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