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zhenek [66]
3 years ago
7

Suppose you are driving a car and your friend, who is with you in the car, tosses a softball up and down from her point of view.

A second friend of yours stands on the street and sees you passing by and says, "You are testing projectile motion with the softball!". Your friend on the street claims that each of you measures a different value for the vertical component of the initial velocity of the softball. Do you agree with the statement?
Physics
1 answer:
Sholpan [36]3 years ago
3 0

Answer:

No, i disagree.

Explanation:

If the car is moving, it only has a velocity with a component in the horizontal direction. If we use galilean relativity, the velocity of the ball observed by my friend standing in the ground should only be affected in the horizonal direction, while the vertical stays the same for both observers.

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Two long, straight wires are separated by a distance of 32.2 cm. One wire carries a current of 2.75 A, the other carries a curre
Igoryamba

Answer:

a)\frac{F_1}{L}=1.95*10^-^5N

b)\frac{F_2}{L}=1.95*10^-^5N

Explanation:

From the question we are told that:

Distance between wires d=32.2

Wire 1 current I_1=2.75

Wire 2 current I_2=4.33

a)

Generally the equation for Force on l_1 due to I_2 is mathematically given by

F_1=I_1B_2L

Where

B_2=Magnetic field current by I_2

B_2=\frac{\mu *i_2}{2\pi d}

Therefore

F_1=I_1B_2L

F_1=I_1(\frac{\mu *i_2*l_1}{2\pi d})L

\frac{F_1}{L} =\frac{4*\pi*10^{-7}*2.75*4.33*100 }{2*\pi*12.2 }

\frac{F_1}{L}=1.95*10^-^5N

b)

Generally the equation for Force on I_2 due to I_1 is mathematically given by

F_2=I_2B_1L

Where

B_1=Magnetic field current by I_2

B_1=\frac{\mu *I_1}{2\pi d}

Therefore

\frac{F_2}{L} =I_2(\frac{\mu *I_1*I_2}{2\pi d})

\frac{F_2}{L}=1.95*10^-^5N

5 0
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Answer:

(A⃗ ×B⃗ )⋅C⃗  = 69.868

Explanation:

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Answer:

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