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noname [10]
3 years ago
10

Compare and contrast the general properties of alloys and pure metals

Chemistry
1 answer:
murzikaleks [220]3 years ago
4 0
Alloys are used much more than pure metals because they are generally stronger and less likely to react with air or water.

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A 4.55 l sample of water contains 0.115 g of sodium ions. determine the concentration of sodium ions in ppm if the density of th
Slav-nsk [51]
<span>When one talks about ppm in a liquid solution someone means mg/L so we would not be using the density. This usually means ug/g or mg/kg 0.115 g Na^+ * 10^6 ug/1 g = 115000 ug/g 4.55 L * 1000 mL/1L = 4550 mL Concentration of Na^+ in ppm: 115000 ug/g /4550 mL = 25.27 pm of sodium ion</span>
6 0
3 years ago
Read 2 more answers
The human body is about 9.5% carbon atoms, with a small fraction of that carbon being radioactive carbon-14. Carbon dating is a
maw [93]

Answer:The age can be determined by utilizing carbon-14, a radioactive isotope of carbon.

Explanation:

8 0
3 years ago
WHO KNOWS HOW TO DO THISSS NEED HELP RN PLS<br><br> Li PO4 + AlF →
Alecsey [184]

Explanation:

Your chemical equation should look like this:

Li3PO4 + AlF3 --> 3LiF + AlPO4

This is the balanced equation for a double-displacement reaction

4 0
3 years ago
Consider the followong balanced reaction. What mads in g of co2 can be formed from 288 mg of o2. Assume that there is excess c3h
Gwar [14]

<u>Answer:</u>

<em>0.264 g of CO_2 can be formed from 288 mg of O_2</em>

<u>Explanation:</u>

The balanced chemical equation is

2 C_3 H_7 OH+9 O_2> 6 CO_2+8 H_2 O

The conversions are  

Mass in mg O_2 is converted to mass in g O_2  

Mass in g O_2 is converted to moles O_2 by dividing with molar mass  

Moles O_2 is converted to moles CO_2  by using the mole ratio of O_2:CO_2 is 9 : 6

Moles CO_2  is converted to mass CO_2 by multiplying with molar mass CO_2

mass in mg O_2  > mass in g O_2 >moles O_2 > moles CO_2 > mass CO_2

288mg O_2 \times \frac{(1g O_2)}{(1000mg O_2 )} \times \frac {(1molO_2)}{(32gO_2 )}\times\frac {(6mol CO_2)}{(9mol O_2 )} \times \frac {(44.0 gCO_2)}{(1mol CO_2 )}

=0.264g (Answer)

7 0
3 years ago
2) 183 cg =<br> kg<br> 5<br> .00183 kg<br> 0.0183 kg<br> .183 kg<br> 3) 0.25 kg =<br> g
OlgaM077 [116]

Answer:

183 cg = 0.00183 kg

0.25 kg = 250 g

Explanation:

Use conversion factors. 1kg is equal to 1 x 10^5 cg (100000) and 1 kg is equal to 1 x 10^3 grams (1000 grams).

5 0
3 years ago
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