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maria [59]
3 years ago
13

Anyone wanna hear a story about my bratty little sister?

Chemistry
2 answers:
svetlana [45]3 years ago
8 0
I would love to lol.

Explanation:
algol [13]3 years ago
8 0

Answer:

Not really but I need the points so sure

Explanation:

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Mark's uncle is about to have a procedure to treat his prostate cancer. The treatment involves placement of small
Slav-nsk [51]

Answer: b. Brachytherapy

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6 0
3 years ago
Using today's current price of gold - $1838.80 per troy ounce, how much are 5.17x1017 atoms of gold worth? (Hint: You will have
Zepler [3.9K]

Answer:

0.010 $.

Explanation:

Hello!

In this case, since 1 troy ounce equals 31.1 grams, we can compute the price of gold per gram first:

1,838.80\frac{\$}{try\ ounce} * \frac{1try\ ounce}{31.1g}  = 59.1\frac{\$}{g}

Now, we need to compute the grams of copper in 5.17 x10¹⁷ atoms via the Avogadro's number:

m=5.17x10^{17}atomsAu*\frac{197.0gAu}{6.022x10^{23}atomsAu} \\\\m=1.69x10^{-4}g

Thus, the price is:

\$ = 59.1\frac{\$}{g}*1.69x10^{-4}g \\\\\$ =0.010\$

Best regards!

7 0
3 years ago
with the help of balanced chemical equation explain what happens when zinc is put in dilute hydrochloric acid
blagie [28]
They react to form salt  ZnCl + hydrogen gas

3 0
3 years ago
The Geologic Time scale helps to divide Earth's long history into more manageable pieces of time.
Alla [95]
4.5 billion years old


Hope this helps!!!
7 0
2 years ago
Read 2 more answers
The rate constant for a certain reaction is k = 5.40×10−3 s−1 . If the initial reactant concentration was 0.100 M, what will the
IceJOKER [234]

Answer : The concentration after 17.0 minutes will be, 4.05\times 10^{-4}M

Explanation :

The expression for first order reaction is:

[C_t]=[C_o]e^{-kt}

where,

[C_t] = concentration at time 't'  (final) = ?

[C_o] = concentration at time '0' (initial) = 0.100 M

k = rate constant = 5.40\times 10^{-3}s^{-1}

t = time = 17.0 min = 1020 s (1 min = 60 s)

Now put all the given values in the above expression, we get:

[C_t]=(0.100)\times e^{-(5.40\times 10^{-3})\times (1020)}

[C_t]=4.05\times 10^{-4}M

Thus, the concentration after 17.0 minutes will be, 4.05\times 10^{-4}M

4 0
3 years ago
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