1.3*10^1 would be the answer
The empirical formula of c12h24o12 is a carbohydrate.
<h3>Carbohydrate</h3>
A carbohydrate is a biomolecule made up of carbon (C), hydrogen (H), and oxygen (O) atoms, often with a hydrogen-oxygen atom ratio of 2:1 (as in water), and so having the empirical formula Cm(H2O)n (where m may or may not be different from n). All molecules that meet this exact stoichiometric criterion are not, however, automatically categorized as being carbohydrates.
The term is most frequently used in biochemistry, where it is used as a synonym for saccharide, a class of compounds that includes sugars, starches, and cellulose. The four chemical categories of saccharides are monosaccharides, disaccharides, oligosaccharides, and polysaccharides. The smallest carbohydrates, monosaccharides and disaccharides, are sometimes referred to as sugars.
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Answer:

Explanation:
Hello there!
In this case, according to the given chemical reaction, it is possible to realize there is a 1:2 mole ratio of sulfuric acid to water; thus, given the mass of the former and its molar mass (98.07 g/mol), it is possible to determine the mass of produced water as shown below:

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Answer:
B
Explanation:
Trees have a major impact on the amount of carbon dioxcide, as they take it in in exchange for oxygen. If someone deforested an area, it would lead to higher levels or the gas in the air.
Answer:
Percent yield = 61.58%
Explanation:
C4H9OH + NaBr + H2SO4 --> C4H9Br + NaHSO4 + H2O
From the reaction;
1 mol of C4H9OH reacts with 1 mol of NaBr and 1 mol of H2SO4 to form 1 mol of C4H9Br
We have to obtain the limiting reagent. We do this by calculatig the mols of each reactant in the reaction;
Number of moles = Mass / Molar mass
C4H9OH; 15 / 74g/mol = 0.2027
NaBr; 22.4 / 102.89 = 0.2177
H2SO4; 32.7 / 98 = 0.3336
In this case, the limiting reagent is C4H9OH, it determines the amount of product formed.
From the stoichometry of the reaction; one mole of C4H9OH forms one mole of C4H9Br. This means 0.2027 mol of C4H9Br was formed.
Mass = Number of moles * Molar mass
Mass of C4H9Br formed = 0.2027 * 137
Mass = 27.77g
Percent yield = (Practical yield / theoretical yeield ) * 100%
Percent Yield = 17.1 / 27.77 * 100
Percent yield = 61.58%