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xxMikexx [17]
3 years ago
10

Identify the spectator ions in this reaction. Check all that apply. 2H+ + CrO4– + Ba2+ + 2OH– Ba2+ + CrO4– + 2H2O H+ CrO4– Ba2+

OH– 2H2O
Chemistry
2 answers:
Luba_88 [7]3 years ago
6 0

Answer: B and C on the tenth question of the assignment

bagirrra123 [75]3 years ago
5 0
Answer: CrO₄⁻ and  Ba²⁺


Explanation:


1) Chemical equation given:


2H⁺ + CrO₄⁻ + Ba²⁺ + 2OH⁻ → Ba²⁺ + CrO₄⁻ + 2H₂O


2) Analysis


That is an oxidation-reduction equation (some species are been oxidized and others are being reduced).


The given equation is known as total ionic equation, because it shows all the species as ions that are part of the reaction.


2) Specator ions


Spectator ions are the ions that do not change their oxidation state and are easily identified as they are the same in the reactant and product sides.


Here the ions that are the same in the reactant and product sides are:

CrO₄⁻ and  Ba²⁺


3) Addtitional explanation.


Once you identify the spectator ions you can delete them from the equation to obtain the net ionic equation , which in this case turns to be:


2H⁺ + 2OH⁻ →  2H₂O


But this is  not part of the question; it is some context to help you understand the use of the spectator ions concept.
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2 NaOH + H2SO4 → 2 H2O + Na2SO4<br> How many grams of water are produced from 203.50 grams of H2S04?
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Answer:

m_{H_2O}=74.8gH_2O

Explanation:

Hello there!

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m_{H_2O}=203.50gH_2SO_4*\frac{1molH_2SO_4}{98.07gH_2SO_4}*\frac{2molH_2O}{1molH_2SO_4}  *\frac{18.02gH_2O}{1molH_2O}\\\\m_{H_2O}=74.8gH_2O

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ohaa [14]

Answer:

Percent yield = 61.58%

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From the stoichometry of the reaction; one mole of C4H9OH forms one mole of C4H9Br. This means 0.2027 mol of C4H9Br was formed.

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