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FromTheMoon [43]
3 years ago
8

Which electrons are lost by an atom of iron when it forms the Fe3+ ion?

Chemistry
2 answers:
astra-53 [7]3 years ago
8 0
The two s Orbital electrons and one d orbital electron, are the electrons that are lost by an atom of Iron when it forms the Fe3 + ion. 
Varvara68 [4.7K]3 years ago
5 0
<span>B. Two s orbital electrons and one d orbital electron</span>
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Look up and record the boiling point of acetic acid, and explain why only some of it evaporates from the reaction mixture.
REY [17]

Answer:

Heating the mixture to a temperature above the boiling point of acetic acid, but below 100°C (the boiling point of water). The vapours from the acetic acid rise, and go into a tube. They are then condensed within the tube, and run off into a separate storage area. Because water can exist as a gas at pretty much any temperature above 0°C, it will result in an impure mixture, but repeatedly doing this will get the acetic acid to the desired purity.

8 0
3 years ago
9.11 moles of vanadium to atoms
marshall27 [118]
Using the Avogadro's number (6.022*10^23)

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3 0
4 years ago
A particular graduated cylinder contains 24.0 mL Br2(liquid). The density of bromine at 25 degrees C is 3.12g/cm^3. Note that in
motikmotik

Answer:

2.82x10^{23}molecules

Explanation:

Hello.

In this case, given the volume (1cm³=1mL) and density of the bromine we are to firstly compute the mass since it will allow us to compute the representative particles:

\rho =\frac{m}{V}

m=\rho *V=3.12g/cm^3*24.0cm^3\\\\m=74.88gBr_2

Next, since the mass of one mole of diatomic bromine is 159.82 g (one bromine weights 78.91), we can next compute the moles in that sample:

n=74.88g*\frac{1mol}{159.82g} =0.469molBr_2

Finally, via the Avogadro's number we can compute the representative particles of bromine as follows:

particles=0.469mol*\frac{6.022x10^{23}molecules}{1mol}\\ \\2.82x10^{23}molecules

Best regards.

4 0
3 years ago
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Ymorist [56]

Answer:

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4 years ago
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3 years ago
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