Answer:
Any two used of mixtures are 1) sand and water 2) sugar and salt
Explanation:
Answer:
CH4
Explanation:
In solving this problem, we must remember that one mole of a compound contains Avogadro's number of elementary entities. These elementary entities include atoms, molecules, ions etc. Recall that one mole of a substance is the amount of substance that contains the same number of elementary entities as 12g of carbon-12. The Avogadro's number is 6.02 × 10^23.
Hence we can now say;
If 163 g of the compound contains 6.13 ×10^24 molecules
x g will contain 6.02 × 10^23 molecules
x= 163 × 6.02 × 10^23 / 6.13 × 10^24
x= 981.26 × 10^23/ 6.13 ×10^24
x= 160.1 × 10^-1 g
x= 16.01 g
x= 16 g(approximately)
16 g is the molecular mass of methane hence x must be methane (CH4)
1023 molecules or atoms depending on substance
Answer:
195.199grams
Explanation:
Fluorine has a molar mass of 18.99984 while calcium has a molar mass of calcium is 40.08.
1 mole of calcium fluoride has a mass of 40.08+2×18.99984
=78.0797 grams
if one mole has a mass of 78.0797 grams, then 2.5 moles have:
2.5 moles× 78.0797 grams/mole= 195.1992 grams
