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wolverine [178]
2 years ago
8

Pt 2. Chem Reactions 50 PTS

Chemistry
1 answer:
Dahasolnce [82]2 years ago
6 0

The red colour is the limiting reactant.

Red-blue colour ball and two white balls attached together are reactants.

Red-blue colour ball and two white and one red colour ball attached to each other are products.

<h3>What is a limiting reagent?</h3>

The reactant that is entirely used up in a reaction is called a limiting reagent.

A reactant is a substance that is present at the start of a chemical reaction. The substance(s) to the right of the arrow are called products.

A product is a substance that is present at the end of a chemical reaction.

Hence,

The red colour is the limiting reactant.

Red-blue colour ball and two white balls attached together are reactants.

Red-blue colour ball and two white and one red colour ball attached to each other are products.

Learn more about limiting reagents here:

brainly.com/question/26905271

#SPJ1

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Find the pH of a 0.100 molar H2C6O6 solution with ka, where KA is equal 8.0×10–5​
lubasha [3.4K]

The pH of the solution is 2.54.

Explanation:

pH is the measure of acidity of the solution and Ka is the dissociation constant. Dissociation constant is the measure of concentration of hydrogen ion donated to the solution.

The solution of C₆H₂O₆ will get dissociated as C₆HO₆ and H+ ions. So the molar concentration of 0.1 M is present at the initial stage. Lets consider that the concentration of hydrogen ion released as x and the same amount of the base ion will also be released.

So the dissociation constant Kₐ can be written as the ratio of concentration of products to the concentration of reactants. As the concentration of reactants is given as 0.1 M and the concentration of products is considered as x for both hydrogen and base ion. Then the

K_{a}=\frac{[H^{+}][HB] }{[reactant]}

[HB] is the concentration of base.

8 * 10^{-5} =\frac{x^{2}  }{0.1}\\\\\\x^{2} = 8 * 10^{-5}*0.1

x^{2} = 0.08 * 10^{-4}\\ \\x = 0.283*10^{-2}

Then

pH = - log [x] = - log [ 0.283 * 10^{-2}]\\ \\pH = 2 + 0.548 = 2.54

So the pH of the solution is 2.54.

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