Answer:
Explanation:
The following are the order of point from oldest to most recent
1. Atoms are tiny indivisible particles that make up all mater.
it is Postulate of Dalton's atomic theory. this theory was put forward in 1803
2. Negatively charged electrons are embedded in a mass of positive charge.
In 1897 J.J Thomson discovered that atom consist of tiny negatively charged particles called electrons that are uniformly spread in +vely charged matrix this model called as plum pudding model.
3. Atoms consist of mostly empty space with a dense nucleus of positive charge.
While doing experiment on gold foil Rutherford presented a model in 1909 and stated that atom consist mostly empty space with dense nucleus.
4. Electrons occupy specific energy levels surrounding a positively charged nucleus.
Niels Bohr in 1913 put forward a model to explain atomic orbitals/energy level. This is a postulate of Bohr model.
5. Electrons move about a positively charged nucleus in clouds that are defined by probabilities.
In 1926 Erwin Schrödinger explain the wave function of electrons and its probability.
Answer:
C.
Explanation:
Noble gases are stable and already have a full outter shell therefore don't tend to lose or gain any electrons.
A mol=6.02*10^23
so
distance from earth to moon is 230,100 miles
1 big mac is about 2 inches
1 mile=5280 feet=63360inches
230,100 times 63360=14,579,136,000 inches is distance
6.02 times 10^23 times 2=x times 14,579,136,000
divide both sides by 2
6.02 times 10^23=x times 7,289,568,000
divide both sides by 6.02
10^23=x times 1210891694.35159
divide both sides by 1210891694.35159
825583769024485.8
about 825,583,769,024,486 times
Data Given:
Pressure = P = 0.5 atm
Volume = V = 2.0 L
Temperature = T = 50 °C + 273 = 323 K
Moles = n = ?
Solution:
Let suppose the gas is acting Ideally, Then According to Ideal Gas Equation.
P V = n R T
Solving for n,
n = P V / R T
Putting Values,
n = (0.5 atm × 2.0 L) ÷ (0.0821 atm.L.mol⁻¹.K⁻¹ × 323 K)
n = 0.0377 mol
I believe the answer you're looking for is B. It's Polluted. I hope this helps.
