According to the research, the correct option is exocytosis. Insulin is made by pancreatic cells, packaged in small vesicles, and then released into the bloodstream. This describes <u>exocytosis</u> cell transport.
What is exocytosis?
It is the expulsion, by cells, of particles that, due to their size, cannot pass through the cell membrane.
In this sense, it is the process by which different types of molecules contained in a cytoplasmic vesicle of a cell are secreted. Insulin is released to the outside by exocytosis, intervening in the process of glucose entry into cells.
Therefore, we can conclude that according to the research, the correct option is exocytosis. Insulin is made by pancreatic cells, packaged in small vesicles, and then released into the bloodstream. This describes <u>exocytosis</u> cell transport.
Learn more about exocytosis here: brainly.com/question/1193597
#SPJ1
Diffraction occurs when a wave moves through an opening in a barrier. This causes the wave to change direction and spread out.
Waves can behave in three different ways depending on the obstacles they encounter. They can reflect, refract or diffract. In diffraction, waves such as sound, light or water either bend around small objects that obstruct their passage or spread out as they travel through a gap in the barrier.
The degree of diffraction forms a direct relationship with wavelength. It generally increases as wavelength increases. Conversely, the amount of bending lessens as wavelength decreases. However, if the opening of the barrier is smaller than the wavelength, the effect of diffraction is not easily observed. Hope this helps.
Answer:
d.0.48
Explanation:
When a population is in Hardy Weinberg equilibrium the <u>genotypic </u>frequencies are:
freq (AA) = p²
freq (Aa) = 2pq
freq (aa) = q²
<em>p</em> is the frequency of the dominant <em>A</em> allele and <em>q</em> is the frequency of the recessive <em>a</em> allele.
In this population of 100 individuals, 84 martians have the dominant phenotype and 16 have the recessive phenotype.
Therefore:
q²=16/100
q² = 0.16
q=√0.16
q = 0.4
And p+q=1, so:
p = 1 - q
p = 1-0.4
p = 0.6
The frequency of heterozygotes is:
freq (Aa) = 2pq = 2 × 0.4 × 0.6
freq (Aa) = 0.48
It has two layers.
Hope I could help :)
